我正在使用 Django 和 Django Rest Framework 构建 API
我有以下端点:
host/products/指向ModelViewSet,所以我有一个为指定模型工作的 CRUD。
此外,我使用以下代码为名为config的嵌套模型定义了一个额外的操作:
@action(detail=False, methods=['get', 'post'])
def config(self, request, *args, **kwargs):
if request.method == 'GET':
return super().list(request, *args, **kwargs)
elif request.method == 'POST':
return super().create(request, *args, **kwargs)
创建的 URL 为: host/products/config/
在此 URL,我可以在第二个指定模型中创建和列出对象
问题是我想为嵌套 URL 包含PATCH和DELETE方法,我的意思是:
host/products/config/ detail /
我尝试做这样的事情:
@action(detail=True)
@config.mapping.patch
def update_config(self, request, *args, **kwargs):
return super().update(request, *args, **kwargs)
但是,当然,它不起作用......
如何将详细信息操作映射到同一视图集中的另一个操作?
完整代码如下:
class ProductViewSet(viewsets.ModelViewSet):
def get_permissions(self):
''' Assign permissions based on action. '''
if self.action in ['suggestions']:
permission_classes = [AllowAny]
else:
permission_classes = [AllowAny] # [IsAdminUser | IsDevUser]
return [permission() for permission in permission_classes]
def get_queryset(self):
''' Return queryset based on action. '''
if self.action == 'config':
# Return product details
return ProductDetails.objects.filter(active=True)
else:
# Return active products
return Product.objects.filter(active=True)
def get_serializer_class(self):
''' Return serializer based on action. '''
if self.action == 'suggestions':
return SurveySerializer
elif self.action == 'config':
return ProductDetailModelSerializer
else:
return ProductModelSerializer
@action(detail=False, methods=['get', 'post'])
def config(self, request, *args, **kwargs):
if request.method == 'GET':
return super().list(request, *args, **kwargs)
elif request.method == 'POST':
return super().create(request, *args, **kwargs)
@action(detail=True)
@config.mapping.patch
def update_config(self, request, *args, **kwargs):
return super().update(request, *args, **kwargs)