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我有 1 个订单号，其中包含 4 个 sku，每个 sku 都链接到 3 个类别：

在此处输入图像描述

我需要编写一条 SQL 语句将其转换为 JSON 格式，其中涉及子查询和数组中的多个元素。基本上我需要它看起来像这样：

{
    "order_number": "WEB000000000",
    "order_items": [
        {
            "sku": 111111111,
            "categories": ["Checked Shirts", "Mens", "Shirts"]
        },
        {
            "sku": 333333333,
            "categories": ["Accessories & Shoes", "Mens Accessories", "Socks"]
        },
        {
            "sku": 666666666,
            "categories": ["Checked Shirts", "Mens", "Shirts"]
        },
        {
            "sku": 999999999,
            "categories": ["Nightwear", "Slippers", "Womens"]
        }
    ]
}

这是我到目前为止所拥有的，但我无法完全正确：

DROP TABLE IF EXISTS ##Data;
CREATE TABLE ##Data
(
    order_number varchar(100),
    sku bigint,
    categories varchar(100)
);
INSERT INTO ##Data 
select  'WEB000000000', 111111111, 'Mens'
 union all select 'WEB000000000', 111111111, 'Shirts'
 union all select 'WEB000000000', 111111111, 'Checked Shirts'
 union all select 'WEB000000000', 333333333, 'Accessories & Shoes'
 union all select 'WEB000000000', 333333333, 'Mens Accessories'
 union all select 'WEB000000000', 333333333, 'Socks'
 union all select 'WEB000000000', 666666666, 'Mens'
 union all select 'WEB000000000', 666666666, 'Shirts'
 union all select 'WEB000000000', 666666666, 'Checked Shirts'
 union all select 'WEB000000000', 999999999, 'Womens'
 union all select 'WEB000000000', 999999999, 'Nightwear'
 union all select 'WEB000000000', 999999999, 'Slippers'



SELECT * FROM ##Data;



select OUTER1.[order_number] as [order_number],
    (select OSL.[order_number],

            (select [sku], 
                    (select [categories]
                        from ##Data skus
                        where order_item.[order_number] = skus.[order_number]
                            and order_item.[sku] = skus.[sku]
                        GROUP BY [categories]
                    FOR JSON PATH) as categories
            from ##Data order_item
            where order_item.[order_number] = OSL.[order_number]
            GROUP BY [order_number], [sku]
        FOR JSON PATH) as order_items

    from ##Data OSL 
    where OSL.[order_number]=OUTER1.[order_number]
    group by OSL.[order_number]
    FOR JSON PATH, WITHOUT_ARRAY_WRAPPER) AS JSON
from ##Data OUTER1 
group by OUTER1.[order_number]


drop table ##Data
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