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目标：如果 pdf 行包含子字符串，则复制整个句子（跨多行）。

我能够出现print()在。linephrase

现在，一旦我找到这个line，我想返回迭代，直到我找到一个句子终止符：. ! ?，从上一个句子开始，然后再次向前迭代，直到下一个句子终止符。

这样我就可以知道print()该短语所属的整个句子。

但是，我遇到了一个递归错误，无法scrape_sentence()无限运行。

Jupyter 笔记本：

# pip install PyPDF2
# pip install pdfplumber

# ---
# import re
import glob
import PyPDF2
import pdfplumber

# ---
phrase = "Responsible Care Company"
# SENTENCE_REGEX = re.pattern('^[A-Z][^?!.]*[?.!]$')

def scrape_sentence(sentence, lines, index, phrase):
    if '.' in lines[index] or '!' in lines[index] or '?' in lines[index]:
        return sentence.replace('\n', '').strip()
    sentence = scrape_sentence(lines[index-1] + sentence, lines, index-1, phrase)  # previous line
    sentence = scrape_sentence(sentence + lines[index+1], lines, index+1, phrase)  # following line    
    
    sentence = sentence.replace('!', '.')
    sentence = sentence.replace('?', '.')
    sentence = sentence.split('.')
    sentence = [s for s in sentence if phrase in s]
    sentence = sentence[0]  # first occurance
    print(sentence)
    
    return sentence
    
# ---    
    
with pdfplumber.open('../data/gri/reports/GPIC_Sustainability_Report_2020__-_40_Years_of_Sustainable_Success.pdf') as opened_pdf:
    for page in opened_pdf.pages:
        text = page.extract_text()
        lines = text.split('\n')
        i = 0
        sentence = ''
        while i < len(lines):
            if 'and Knowledge of Individuals; Behaviours; Attitudes, Perception ' in lines[i]:
                sentence = scrape_sentence('', lines, i)  # !
                print(sentence)  # !
            i += 1

输出：

connection and the linkage to the relevant UN’s 17 SDGs.and Leadership. We have long realized and recognized that there

短语：

Responsible Care Company

句子（跨多行）：

"GPIC is a Responsible Care Company certified for RC 14001 
since July 2010."

PDF（第 2 页）。

如果还有什么我可以添加到帖子中，请告诉我。

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1 回答 1

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我在这里通过删除任何递归解决了这个问题scrape_sentence()。

于 2021-11-30T10:04:36.720 回答