我有以下代码片段：
df = pd.read_csv("data.csv")
X = df.drop(['label'], axis=1)
Y= df['label']
le = LabelEncoder()
Y = le.fit_transform(Y)
mapping = dict(zip(le.classes_, range(len(le.classes_))))
x_train, x_test, y_train, y_test = train_test_split(X, Y, test_size=0.33, random_state=7,stratify=Y)
##xgb model
model = XGBClassifier()
model.fit(x_train, y_train)
#predict
y_pred = model.predict(x_train)
这里y_pred给出了编码的标签。如何在编码之前获得真正的标签？
使用原始标签和编码标签创建一个字典，使用该字典将 y_pred 映射到真实标签
您可以使用
le.inverse_transform(y_pred)
le装在哪里LabelEncoder
le = LabelEncoder().fit(y)
请参阅文档。
import numpy as np
from sklearn.model_selection import train_test_split
from sklearn.preprocessing import LabelEncoder
from xgboost import XGBClassifier
x = np.random.normal(0, 1, (20, 2))
y = np.array(['a', 'b'] * 10)
print(y)
# ['a' 'b' 'a' 'b' 'a' 'b' 'a' 'b' 'a' 'b' 'a' 'b' 'a' 'b' 'a' 'b' 'a' 'b' 'a' 'b']
le = LabelEncoder().fit(y)
y_enc = le.transform(y)
print(y_enc)
# [0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1]
x_train, x_test, y_train, y_test = train_test_split(x, y_enc, test_size=0.33, random_state=7, stratify=y_enc)
model = XGBClassifier()
model.fit(x_train, y_train)
y_pred_enc = model.predict(x_train)
print(y_pred_enc)
# [1 0 0 0 0 0 0 0 1 1 1 0 1]
y_pred = le.inverse_transform(y_pred_enc)
print(y_pred)
# ['b' 'a' 'a' 'a' 'a' 'a' 'a' 'a' 'b' 'b' 'b' 'a' 'b']