javascript - 是否存在反向逻辑无效赋值？

Question

因此，??=仅当当前存储的值为空值时，运算符才将值分配给变量。

也许我错过了显而易见的事情，但我想不出一个巧妙的解决方案（没有 if 语句）仅在值不为 null 的情况下分配？

我正在使用 nodeJS 来提供更多上下文。

---

我想

let x r??= 2;
// Updates 'x' to hold this new value
x r??= undefined;
// Has no effect, since the value to assign is nullish
console.log(x); // 2

编辑 以更清楚地说明我的问题：

如果该新值不为空，我只想为变量分配一个新值。

let iceCream = {
    flavor: 'chocolate'
}

const foo = 2.5
const bar = undefined;

iceCream.price r??= bar
// does not assign the new value because it is nullish
console.log(iceCream.price) // expected to be error, no such property

iceCream.price r??= foo
// assigns the new value because it is not nullish but a float
console.log(iceCream.price) // expected to be 2.5

iceCream.price r??= bar
// does not assign the new value because it is nullish
console.log(iceCream.price) // expected to still be 2.5

Answer 1

不，这不是一个单一的运营商。最接近的是两个运算符：

x = undefined ?? x;

Answer 2

在澄清后添加另一个答案，因为编辑我以前的答案似乎很奇怪。

我能想到的没有 if 的解决方案的最简单方法如下：

let iceCream = {
    flavor: 'chocolate'
}

const foo = 2.5
const bar = undefined;
bar && (iceCream.price = bar)
// Another possible solution if creating the property with a nullish value is ok for you:
iceCream.price = bar || iceCream.price;

Answer 3

您可以使用逻辑 AND 分配。

来自 MDN 网络文档：

let a = 1;
let b = 0;

a &&= 2;
console.log(a);
// expected output: 2

b &&= 2;
console.log(b);
// expected output: 0