0

所以我有一个给出输出的代码，我需要做的是在逗号之间提取信息，将它们分配给一个在调用时动态变化的变量......这是我的代码：

import re

data_directory = 'Z:/Blender_Roto/'
data_file = 'diving_board.shape4ae'
fullpath = data_directory + data_file


print("====init=====")

file = open(fullpath)
for line in file:
current_line = line

# massive room for optimized code here.

# this assumes the last element of the line containing the words
# "Units Per Second" is the number we are looking for.
# this is a non float number, generally.
if current_line.find("Units Per Second") != -1:
    fps = line_split = float(current_line.split()[-1])
    print("Frames Per Second:", fps)

# source dimensions
if current_line.find("Source Width") != -1:
    source_width = line_split = int(current_line.split()[-1])
    print("Source Width:", source_width)

if current_line.find("Source Height") != -1:
    source_height = line_split = int(current_line.split()[-1])
    print("Source Height:", source_height)

# aspect ratios
if current_line.find("Source Pixel Aspect Ratio") != -1:
    source_px_aspect = line_split = int(current_line.split()[-1])
    print("Source Pixel Aspect Ratio:", source_px_aspect)

if current_line.find("Comp Pixel Aspect Ratio") != -1:
    comp_aspect = line_split = int(current_line.split()[-1])
    print("Comp Pixel Aspect Ratio:", comp_aspect)


# assumption, ae file can contain multiple mocha shapes.
# without knowing the exact format i will limit the script
# to deal with one mocha shape being animated N frames.

# this gathers the shape details, and frame number but does not
# include error checking yet.
if current_line.find("XSpline") != -1:

    # record the frame number.

    frame = re.search("\s*(\d*)\s*XSpline", current_line)
    if frame.group(1) != None:
        frame = frame.group(1)
        print("frame:", frame)


    # pick part the part of the line that deals with geometry
    match = re.search("XSpline\((.+)\)\n", current_line)

    line_to_strip = match.group(1)
    points = re.findall('(\(.*?\))', line_to_strip)

    print(len(points))
    for point in points:
        print(point)
    print("="*40)

file.close()

这给了我输出：

====init=====
Frames Per Second: 24.0
Source Width: 2048
Source Height: 778
Source Pixel Aspect Ratio: 1
Comp Pixel Aspect Ratio: 1
frame: 20
5
(0.793803,0.136326,0,0.5,0)
(0.772345,0.642332,0,0.5,0)
(0.6436,0.597615,0,0.5,0)
(0.70082,0.143387,0,0.5,0.25)
(0.70082,0.112791,0,0.5,0)
========================================

所以我需要例如能够将 (0.793803, 0.136326, 0, 0.5, 0) 分配给 (1x,1y,1z,1w,1s), (0.772345,0.642332,0,0.5,0) 分配给 (2x , 2y, 2z, 2w, 2s) 等，这样无论什么数字填充这些位置，它们都将采用该值。

这是我需要将这些数字放入的代码：

#-------------------------------------------------------------------------------
# Name:        Mocha Rotoscoping Via Blender
# Purpose:     Make rotoscoping more efficient
#
# Author:      Jeff Owens
#
# Created:     11/07/2011
# Copyright:   (c) jeff.owens 2011
# Licence:     Grasshorse
#-------------------------------------------------------------------------------
#!/usr/bin/env python

import sys
import os
import parser
sys.path.append('Z:\_protomotion\Prog\HelperScripts')
import GetDir
sys.path.append('Z:\_tutorials\01\tut01_001\prod\Blender_Test')
filename = 'diving_board.shape4ae'
infile = 'Z:\_tutorials\01\tut01_001\prod\Blender_Test'
import bpy
from mathutils import Vector

#below are taken from mocha export
x_width =2048
y_height = 778
z_depth = 0
frame = 20

def readText():
text_file = open('diving_board.shape4ae', 'r')
lines = text_file.readlines()
print (lines)
print (len.lines)
for line in lines:
    print (line)

##sets points final x,y,z value taken from mocha export for blender interface

point1x = (0.642706 * x_width)
point1y = (0.597615 * y_height)
point1z = (0 * z_depth) 

point2x = (0.770557 * x_width)
point2y = (0.647039 * y_height)
point2z = (0 * z_depth)

point3x = (0.794697 * x_width)
point3y = (0.0869024 * y_height)
point3z = (0 * z_depth)


point4x = (0.707973* x_width)
point4y = (0.0751348 * y_height)
point4z = (0 * z_depth)


w = 1 # weight
listOfVectors = [Vector((point1x,point1y,point1z)),Vector((point2x,point2y,point2z)),Vector((point3x,point3    y,point3z)),Vector((point4x,point4y,point4z)), Vector((point1x,point1y,point1z))]

def MakePolyLine(objname, curvename, cList):
curvedata = bpy.data.curves.new(name=curvename, type='CURVE')
curvedata.dimensions = '3D'

objectdata = bpy.data.objects.new(objname, curvedata)
objectdata.location = (0,0,0) #object origin
bpy.context.scene.objects.link(objectdata)

polyline = curvedata.splines.new('POLY')
polyline.points.add(len(cList)-1)
for num in range(len(cList)):
    x, y, z = cList[num]
    polyline.points[num].co = (x, y, z, w)

MakePolyLine("NameOfMyCurveObject", "NameOfMyCurve", listOfVectors)

所以我有我的矢量我希望能够放置 (px, py,0.z,pw,ps) 然后 (p2.x,p2.y,p2.zp2.wp2.s) 等，这样它就可以根据给定的数字更改

任何帮助都会很棒..提前谢谢你！

-杰夫

4

2 回答 2

3

您可以创建点对象并按名称对它们进行索引，而不是打印每个输出。例如：

>>> class Point:
...     def __init__(self, t):
...         (self.x,self.y,self.z,self.w,self.s) = t
... 
>>> p = Point( (3,4,5,3,1) )
>>> p.w
3

您可以将这些点对象放在一个数组中，然后通过

myPoints[3].x

附录

如果重要的是不要从数组中提取点，而是使用实际的变量名，您可以执行以下操作，points您的元组数组在哪里：

(p0x,p0y,p0z,p0w,p0s) = points[0]
(p1x,p1y,p1z,p1w,p1s) = points[1]
(p2x,p2y,p2z,p2w,p2s) = points[2]
...

等等。

请考虑这是否是一种适当的方法。拥有一个点等级可以让您拥有任意数量的点。使用已定义的变量名称，可以即时创建无限数量的这些东西，但几乎总是一个坏主意。这里有一个关于这样做的警告：http: //mail.python.org/pipermail/tutor/2005-January/035232.html。

当您拥有一组点对象时，您可以做得更好！例如，您可以执行以下操作：

myPoints[i].y = 12

从而改变第 i 个点的 y 坐标。当您修复了变量名称时，这几乎是不可能的。希望有帮助！（希望我能理解你的澄清！如果没有，请告诉我......）

于 2011-08-09T17:07:46.543 回答
0

如果我正确阅读了您的代码，则相关部分是最后生成元组的循环。

data = []
for point in points:
    data.append(point)    
    print(point)

这将创建一个新列表并将每个元组添加到列表中。所以，data[0]持有(0.793803,0.136326,0,0.5,0)并data[0][0]持有0.793803。

于 2011-08-09T17:01:31.193 回答