432

我有一个 Pythondatetime对象,我想将其转换为 1970 年以来的 unix 时间或秒/毫秒。

我该怎么做呢?

4

14 回答 14

533

在我看来,最简单的方法是

import datetime

epoch = datetime.datetime.utcfromtimestamp(0)

def unix_time_millis(dt):
    return (dt - epoch).total_seconds() * 1000.0
于 2012-06-20T00:07:44.323 回答
256

在 Python 3.3 中,添加了新方法timestamp

import datetime
seconds_since_epoch = datetime.datetime.now().timestamp()

你的问题表明你需要毫秒,你可以这样得到:

milliseconds_since_epoch = datetime.datetime.now().timestamp() * 1000

如果您timestamp在幼稚的日期时间对象上使用,则假定它位于本地时区。如果您不打算这样做,请使用时区感知日期时间对象。

于 2014-04-11T05:23:37.240 回答
103
>>> import datetime
>>> # replace datetime.datetime.now() with your datetime object
>>> int(datetime.datetime.now().strftime("%s")) * 1000 
1312908481000

或时间模块的帮助(并且没有日期格式):

>>> import datetime, time
>>> # replace datetime.datetime.now() with your datetime object
>>> time.mktime(datetime.datetime.now().timetuple()) * 1000
1312908681000.0

在以下帮助下回答:http: //pleac.sourceforge.net/pleac_python/datesandtimes.html

文档:

于 2011-08-09T16:48:48.787 回答
17

您可以使用 Delorean 进行时空旅行!

import datetime
import delorean
dt = datetime.datetime.utcnow()
delorean.Delorean(dt, timezone="UTC").epoch

http://delorean.readthedocs.org/en/latest/quickstart.html  

于 2013-05-11T21:07:50.243 回答
14

我就是这样做的:

from datetime import datetime
from time import mktime

dt = datetime.now()
sec_since_epoch = mktime(dt.timetuple()) + dt.microsecond/1000000.0

millis_since_epoch = sec_since_epoch * 1000
于 2013-01-29T12:40:40.580 回答
13

Python 2.7 文档中针对该模块的建议time

在时间表示之间转换

于 2016-07-19T04:20:24.093 回答
10
from datetime import datetime
from calendar import timegm

# Note: if you pass in a naive dttm object it's assumed to already be in UTC
def unix_time(dttm=None):
    if dttm is None:
       dttm = datetime.utcnow()

    return timegm(dttm.utctimetuple())

print "Unix time now: %d" % unix_time()
print "Unix timestamp from an existing dttm: %d" % unix_time(datetime(2014, 12, 30, 12, 0))
于 2014-04-07T17:04:35.377 回答
4

这是另一种形式的时间对象标准化解决方案:

def to_unix_time(timestamp):
    epoch = datetime.datetime.utcfromtimestamp(0) # start of epoch time
    my_time = datetime.datetime.strptime(timestamp, "%Y/%m/%d %H:%M:%S.%f") # plugin your time object
    delta = my_time - epoch
    return delta.total_seconds() * 1000.0
于 2015-02-06T22:57:27.527 回答
3
>>> import datetime
>>> import time
>>> import calendar

>>> #your datetime object
>>> now = datetime.datetime.now()
>>> now
datetime.datetime(2013, 3, 19, 13, 0, 9, 351812)

>>> #use datetime module's timetuple method to get a `time.struct_time` object.[1]
>>> tt = datetime.datetime.timetuple(now)
>>> tt
time.struct_time(tm_year=2013, tm_mon=3, tm_mday=19, tm_hour=13, tm_min=0, tm_sec=9,     tm_wday=1, tm_yday=78, tm_isdst=-1)

>>> #If your datetime object is in utc you do this way. [2](see the first table on docs)
>>> sec_epoch_utc = calendar.timegm(tt) * 1000
>>> sec_epoch_utc
1363698009

>>> #If your datetime object is in local timeformat you do this way
>>> sec_epoch_loc = time.mktime(tt) * 1000
>>> sec_epoch_loc
1363678209.0

[1] http://docs.python.org/2/library/datetime.html#datetime.date.timetuple

[2] http://docs.python.org/2/library/time.html

于 2013-03-19T07:59:15.943 回答
3

一些熊猫代码:

import pandas

def to_millis(dt):
    return int(pandas.to_datetime(dt).value / 1000000)
于 2018-03-19T20:38:29.643 回答
1
import time
seconds_since_epoch = time.mktime(your_datetime.timetuple()) * 1000
于 2011-08-09T16:51:04.927 回答
0

这是我根据上面的答案制作的功能

def getDateToEpoch(myDateTime):
    res = (datetime.datetime(myDateTime.year,myDateTime.month,myDateTime.day,myDateTime.hour,myDateTime.minute,myDateTime.second) - datetime.datetime(1970,1,1)).total_seconds()
    return res

您可以像这样包装返回的值: str(int(res)) 不带十进制值返回它,用作字符串或只返回 int(不带 str)

于 2018-11-18T08:49:43.650 回答
0

其中很多答案不适用于 python 2,或者不保留日期时间的毫秒数。这对我有用

def datetime_to_ms_epoch(dt):
    microseconds = time.mktime(dt.timetuple()) * 1000000 + dt.microsecond
    return int(round(microseconds / float(1000)))
于 2021-12-09T18:14:27.553 回答
-15

这是将日期时间转换为 unixtimestampmillis 的另一种解决方案。

private static readonly DateTime UnixEpoch = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc);

    public static long GetCurrentUnixTimestampMillis()
    {
        DateTime localDateTime, univDateTime;
        localDateTime = DateTime.Now;          
        univDateTime = localDateTime.ToUniversalTime();
        return (long)(univDateTime - UnixEpoch).TotalMilliseconds;
    } 
于 2016-10-20T09:34:38.280 回答