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我正在尝试让 RapidAPI 的 API R 代码工作。

他们提供的代码如下（示意图）：

library(httr)

GET(
  url = rapidapi_url,
  config = list(x-rapidapi-key = API_KEY,
                x-rapidapi-host = HOST_URL,
                useQueryString = TRUE),
  inboundpartialdate = "2019-12-01"
)

此代码不起作用，因为（开始）变量包含减号。

我将代码更改为以下格式

#Define Constants
x_rapidapi_key <- xyz # defined higher up in the script for confidentiality reasons and works in rapidapi.com
HTML_link <- "https://yh-finance.p.rapidapi.com/stock/v3/get-historical-data"
YH_file_type = "json"

#' Paste the get_text together
get_text <- paste(HTML_link,
                  "?q=TTF",
                  "&x-rapidapi-host:",x_rapidapi_host,
                  "&x-rapidapi-key:",x_rapidapi_key,
                  "&out=",YH_file_type,sep="")
httr::GET(get_text)

运行此脚本时，我收到 401 错误，尽管当我在 RapidAPI 中测试 api-key 时一切正常。

Response [https://yh-finance.p.rapidapi.com/stock/v3/get-historical-data?q=TTF&x-rapidapi-host:yh-finance.p.rapidapi.com&x-rapidapi-key:xyz&out=json]
  Date: 2021-11-08 14:16
  Status: 401
  Content-Type: application/json
  Size: 91 B

我在响应中编辑了 api-key。

请参阅下面的相同内容的另一个变体：


library(httr)

url <- "https://yh-finance.p.rapidapi.com/stock/v3/get-historical-data"

queryString <- list(
  symbol = "TTF=F",
  region = "US"
)

response <- VERB("GET",
                 url,
                 add_headers(x_rapidapi_host = 'yh-finance.p.rapidapi.com',
                             x_rapidapi_key = 'xyz'),
                 query = queryString,
                 content_type("application/octet-stream"))
response

content(response, "text")

有谁知道如何使这项工作？

谢谢您的帮助，

迈克尔

4

1 回答 1

0

备案：问题已解决：

library(httr)

queryString <- list(
  symbol = "TTF=F",
  region = "US"
)

res <- GET("https://yh-finance.p.rapidapi.com/stock/v3/get-historical-data",
    add_headers(`x-rapidapi-host`='yh-finance.p.rapidapi.com',
                `x-rapidapi-key`= '[your API Key]'),
    query = queryString)


data <- jsonlite::fromJSON(rawToChar(res$content))

秘密似乎是正确的'和'的组合。不知道为什么这会产生如此大的差异，但它确实有效。

问候，迈克尔

于 2021-11-09T07:39:58.370 回答