我的方法
DELIMITER $$
CREATE FUNCTION fibonacci(num INT)
RETURNS INT
DETERMINISTIC
BEGIN
DECLARE fib1 INT DEFAULT 0;
DECLARE fib2 INT DEFAULT 1;
DECLARE fib3 INT DEFAULT 0;
DECLARE str VARCHAR(255) DEFAULT '01';
IF num = 1 THEN
RETURN fib1;
ELSEIF num = 2 THEN
RETURN CONCAT(fib1, fib2);
ELSE
WHILE num > 2 DO
SET fib3 = fib1 + fib2;
SET fib1 = fib2;
SET fib2 = fib3;
SET num = num - 1;
SET str = CONCAT(str, fib3);
END WHILE;
RETURN str;
END IF;
END $$
DELIMITER ;
如果我使用 SELECT fibonacci(6) 调用上述函数;它返回没有前导零(0)的 11235。我怎样才能显示前导零?