3

这是解释器命令的副本:

scala>val myTable = Array(Array(1))
res30: Array[Array[Int]] = Array(Array(1))

scala> myTable.map(_.map(_.toString))
res31: Array[Array[java.lang.String]] = Array(Array(1))

scala> var result = 0
result: Int = 0

scala> myTable.head
res32: Array[Int] = Array(1)

//note how applying this works
scala> res32.map(elem => if(3> result) result = 3)
res34: Array[Unit] = Array(())

scala> result
res35: Int = 3

//this also works
scala> myTable.map(_.map(_.toString))
res31: Array[Array[java.lang.String]] = Array(Array(1))

//when you combine the double map application and the anonymous function from earlier:
scala> myTable.map(_.map(elem => if(3 > result) result = 3))
java.lang.IllegalArgumentException
    at java.lang.reflect.Array.newArray(Native Method)
    at java.lang.reflect.Array.newInstance(Array.java:52)
    at scala.reflect.ClassManifest$class.arrayClass(ClassManifest.scala:107)
    at scala.reflect.Manifest$$anon$9.arrayClass(Manifest.scala:152)
    at scala.reflect.Manifest$class.arrayManifest(Manifest.scala:46)
    at scala.reflect.Manifest$$anon$9.arrayManifest(Manifest.scala:152)
    at scala.reflect.Manifest$$anon$9.arrayManifest(Manifest.scala:152)
    at scala.reflect.ClassManifest$.arrayType(ClassManifest.scala:205)
    at .<init>(<console>:45)
    at .<clinit>(<console>)
at .<init>(<console>:11)
at .<clinit>(<console>)
at $export(<console>)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at scala.tools.nsc.interpreter.IMain$ReadEvalPrint.call(IMain.scala:592)
at scala.tools.nsc.interpreter.IMain$Request$$anonfun$10.apply(IMain.scala:828)
at scala.tools.nsc.interpreter.Line$$anonfun$1.apply$mcV$sp(Line.scala:43)
at scala.tools.nsc.io.package$$anon$2.run(package.scala:31)
at java.lang.Thread.run(Thread.java:662)

这是预期的行为吗?

4

2 回答 2

5

首先,您应该使用 foreach,而不是 map,但您已经知道 :-)

您正在尝试创建 Unit 数组的数组,该数组在 java 中被转换为 Void.TYPE。这会导致 IllegalArgumentException。

于 2011-08-08T10:57:27.503 回答
3

Scala 用于在调用java.lang.reflect.Array.newInstance时动态创建数组。此方法 不接受大小为零因为,您的 lambda 返回一个类型为 的空数组,其大小为零,在调用外部映射时会出现异常。mapArray[Unit]

顺便说一句,在这个例子中,你真的应该使用,foreach因为你不是试图将数组映射到另一个数组,而是使用副作用:

scala> myTable.foreach(_.foreach(elem => if(3 > result) result = 3))

scala> result
res21: Int = 3

编辑:我误解了这个问题(参见MatthieuF的回答)。问题不在于数组的大小,而在于类型。只需:

scala> java.lang.reflect.Array.newInstance(classOf[Unit], 1)
java.lang.IllegalArgumentException
at java.lang.reflect.Array.newArray(Native Method)
at java.lang.reflect.Array.newInstance(Array.java:52)
at .<init>(<console>:8)
...
于 2011-08-08T10:43:58.183 回答