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您可以在其中选择 eye_color、hair_color、sex... 从特征表中选择 eye_color 的每个值(例如“深棕色”)=每个 hair_color(“深棕色”)然后运行查询。
我终于找到了 MySQL 的解决方案:
SELECT eye_color=hair_color, sex... FROM characteristics WHERE eye_color=hair_color = '1';