我已经根据来自这里、这里、这里和这里的信息编写了一个 2D Perlin 噪声实现。但是,输出看起来像这样。
public static double Perlin(double X, double XScale, double Y, double YScale, double Persistance, double Octaves) {
double total=0.0;
for(int i=0;i<Octaves;i++){
int frq = (int) Math.Pow(2,i);
int amp = (int) Math.Pow(Persistance,i);
total += InterpolatedSmoothNoise((X / XScale) * frq, (Y / YScale) * frq) * amp;
}
return total;
}
private static double InterpolatedSmoothNoise (double X, double Y) {
int ix = (int) Math.Floor(X);
double fx = X-ix;
int iy = (int) Math.Floor(Y);
double fy = Y-iy;
double v1 = SmoothPerlin(ix,iy); // --
double v2 = SmoothPerlin(ix+1,iy); // +-
double v3 = SmoothPerlin(ix,iy+1);// -+
double v4 = SmoothPerlin(ix+1,iy+1);// ++
double i1 = Interpolate(v1,v2,fx);
double i2 = Interpolate(v3,v4,fx);
return Interpolate(i1,i2,fy);
}
private static double SmoothPerlin (int X, int Y) {
double sides=(Noise(X-1,Y,Z)+Noise(X+1,Y,Z)+Noise(X,Y-1,Z)+Noise(X,Y+1,Z)+Noise(X,Y,Z-1)+Noise(X,Y,Z+1))/12.0;
double center=Noise(X,Y,Z)/2.0;
return sides + center;
}
private static double Noise (int X, int Y) {
uint m_z = (uint) (36969 * (X & 65535) + (X >> 16));
uint m_w = (uint) (18000 * (Y & 65535) + (Y >> 16));
uint ou = (m_z << 16) + m_w;
return ((ou + 1.0) * 2.328306435454494e-10);
}
感谢您对错误的任何输入。
编辑:我找到了解决此问题的方法:我使用加载时生成的双精度数组来解决此问题。不过,任何实现良好随机数生成器的方法都值得赞赏。