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我正在努力在 pyspark 上的 pandas 上使用 pandas UDF。你能帮我理解这是如何实现的吗？以下是我的尝试：

import pyspark
from pyspark.sql import SparkSession
from pyspark.sql.functions import pandas_udf
from pyspark import pandas as ps
spark = SparkSession.builder.getOrCreate()
df = ps.DataFrame({'A': 'a a b'.split(),
                   'B': [1, 2, 3],
                   'C': [4, 6, 5]}, columns=['A', 'B', 'C'])
@pandas_udf('float')
def agg_a(x):
    return (x**2).mean()
@pandas_udf('float')
def agg_b(x):
    return x.mean()
spark.udf.register('agg_a_',agg_a)
spark.udf.register('agg_b_',agg_b)
df_means = df.groupby('A')
dfout=df_means.agg({'B':'agg_a_','C':'agg_b_'})

这导致我难以理解的异常：

AnalysisException: expression 'B' is neither present in the group by, nor is it an aggregate function. Add to group by or wrap in first() (or first_value) if you don't care which value you get.;
Aggregate [__index_level_0__#14], [__index_level_0__#14, agg_a_(B#2L) AS B#15, agg_b_(C#3L) AS C#16]
+- Project [A#1 AS __index_level_0__#14, A#1, B#2L, C#3L]
   +- Project [__index_level_0__#0L, A#1, B#2L, C#3L, monotonically_increasing_id() AS __natural_order__#8L]
      +- LogicalRDD [__index_level_0__#0L, A#1, B#2L, C#3L], false

我尝试使用udf而不是pandas_udf但是，同样的异常也失败了

我也尝试仅在一列上使用带有 UDF 的 groupby ，但这也失败了：

import pyspark
from pyspark.sql import SparkSession
from pyspark.sql.functions import udf
from pyspark import pandas as ps
spark = SparkSession.builder.getOrCreate()
df = ps.DataFrame({'A': 'a a b'.split(),
                   'B': [1, 2, 3],
                   'C': [4, 6, 5]}, columns=['A', 'B', 'C'])
@udf('float')
def agg_a(x):
    return (x**2).mean()
@udf('float')
def agg_b(x):
    return x.mean()
spark.udf.register('agg_a_',agg_a)
spark.udf.register('agg_b_',agg_b)
df_means = df.groupby('A')['B']
dfout=df_means.agg('agg_a_')

输出：

PandasNotImplementedError: The method `pd.groupby.GroupBy.agg()` is not implemented yet.

我猜这不是真的。如果我不使用 UDF 并使用已定义的函数，如“min”、“max”，我可以使用 groupby。

我尝试在不按列指定不同 UDF 的情况下使用，但也失败了：

import pyspark
from pyspark.sql import SparkSession
from pyspark.sql.functions import udf
from pyspark import pandas as ps
spark = SparkSession.builder.getOrCreate()
df = ps.DataFrame({'A': 'a a b'.split(),
                   'B': [1, 2, 3],
                   'C': [4, 6, 5]}, columns=['A', 'B', 'C'])
@udf('float')
def agg_a(x):
    return (x**2).mean()
@udf('float')
def agg_b(x):
    return x.mean()
spark.udf.register('agg_a_',agg_a)
spark.udf.register('agg_b_',agg_b)
df_means = df.groupby('A')
dfout=df_means.agg('agg_a_')

输出：

AnalysisException: expression 'B' is neither present in the group by, nor is it an aggregate function. Add to group by or wrap in first() (or first_value) if you don't care which value you get.;
Aggregate [__index_level_0__#14], [__index_level_0__#14, agg_a_(B#2L) AS B#15, agg_a_(C#3L) AS C#16]
+- Project [A#1 AS __index_level_0__#14, A#1, B#2L, C#3L]
   +- Project [__index_level_0__#0L, A#1, B#2L, C#3L, monotonically_increasing_id() AS __natural_order__#8L]
      +- LogicalRDD [__index_level_0__#0L, A#1, B#2L, C#3L], false
4

1 回答 1

2

根据GroupedData.agg文档，您需要定义您的pandas_udfwith PandasUDFType。如果您需要聚合，那么它将是PandasUDFType.GROUPED_AGG.

from pyspark.sql.functions import pandas_udf, PandasUDFType

@pandas_udf('float', PandasUDFType.GROUPED_AGG)
def agg_a(x):
    return (x**2).mean()

@pandas_udf('float', PandasUDFType.GROUPED_AGG)
def agg_b(x):
    return x.mean()

spark.udf.register('agg_a_',agg_a)
spark.udf.register('agg_b_',agg_b)

df.groupby('A').agg({'B':'agg_a_','C':'agg_b_'}).show()

# +---+---------+---------+
# |  A|agg_a_(B)|agg_b_(C)|
# +---+---------+---------+
# |  b|      9.0|      5.0|
# |  a|      2.5|      5.0|
# +---+---------+---------+
于 2021-10-27T03:07:01.340 回答