我有一张像
c1 c2 c3 c4
-----------------
2 1 7 13
9 2 8 14
1 3 9 15
5 4 10 16
2 5 11 17
11 6 12 18
一般来说,我不知道要获得以下形式的字符串的列数(在代码@d 此处为 4):
2,9,1,5,2,11, 1,2,3,4,5,6, 7,8,9,10,11,12, 13,14,15,16,17,18
为此,我正在做:
DECLARE @d INT
,@counterI INT
,@template AS nvarchar(max)
SET @d = 4;
SET @counterI = 1;
Set @template = 'SELECT STUFF(
( SELECT '','' + CAST([col] AS VARCHAR) FROM (';
WHILE (@counterI < @d) BEGIN
SET @template += ' SELECT [c'+CAST(@counterI-1 AS VARCHAR)+'] AS col FROM [MyTable] UNION ALL ';
SET @counterI = @counterI + 1;
END
Set @template += ' SELECT [c'+CAST(@counterI-1 AS VARCHAR)+'] AS col FROM [MyTable] '
Set @template += ') alldata FOR XML PATH('''') ) , 1 , 1 , '''' )';
declare @CommaString varchar(max)
set @CommaString = ''
exec sp_executesql @template, N'@CommaString varchar(max) out', @CommaString out
所以如果我这样做
select @CommaString;
@CommaString
如果在执行 sp_executesql 时打印正确,为什么不选择它返回字符串?