php - PDO Mysql准备好的语句last_insert_id在多插入时返回错误值？

Question

我注意到，如果我准备一个多插入语句并通过 PDO 将其执行到 MySQL 中，然后请求 last_insert_id，我会得到多个插入行的第一个 ID，而不是最后一个。具体来说：

"INSERT INTO test_table (value1, value2, value3) VALUES (1, 2, 3), (1, 2, 3)";

将在一个空表上创建这些行：

ID value1 value2 value3
1    1      2      3
2    1      2      3

但 last_insert_id 将返回“1”。这是一个已知问题还是我做错了什么？有人可以验证/测试/解释这一点吗？我不知道该怎么做才能获得正确的最后一个 ID，除了进行实际选择会慢得多。

Answer 1

这是正确的mysql行为

http://dev.mysql.com/doc/refman/5.0/en/information-functions.html#function_last-insert-id

mysql> USE test;
Database changed
mysql> CREATE TABLE t (
    ->   id INT AUTO_INCREMENT NOT NULL PRIMARY KEY,
    ->   name VARCHAR(10) NOT NULL
    -> );
Query OK, 0 rows affected (0.09 sec)

mysql> INSERT INTO t VALUES (NULL, 'Bob');
Query OK, 1 row affected (0.01 sec)

mysql> SELECT * FROM t;
+----+------+
| id | name |
+----+------+
|  1 | Bob  |
+----+------+
1 row in set (0.01 sec)

mysql> SELECT LAST_INSERT_ID();
+------------------+
| LAST_INSERT_ID() |
+------------------+
|                1 |
+------------------+
1 row in set (0.00 sec)

mysql> INSERT INTO t VALUES
    -> (NULL, 'Mary'), (NULL, 'Jane'), (NULL, 'Lisa');
Query OK, 3 rows affected (0.00 sec)
Records: 3  Duplicates: 0  Warnings: 0

mysql> SELECT * FROM t;
+----+------+
| id | name |
+----+------+
|  1 | Bob  |
|  2 | Mary |
|  3 | Jane |
|  4 | Lisa |
+----+------+
4 rows in set (0.01 sec)

mysql> SELECT LAST_INSERT_ID();
+------------------+
| LAST_INSERT_ID() |
+------------------+
|                2 |
+------------------+
1 row in set (0.00 sec)