我在从集合中擦除元素时遇到了麻烦。我BUILD FAILED
从:
n2Ar.erase(it);
n3Ar.erase(it);
it
从函数接收到的指针在哪里find()
:例如it = n2Ar.find(*i);
整个程序清单:
#include <stdio.h>
#include <iostream>
#include <vector>
#include <set>
#include <algorithm>
using namespace std;
#define TESTING_FILE_IN
//#define TESTING_FILE_OUT
//#define DEBUG
//#define SHOW_TIMING
int outputSet(int i) {
cout << i << endl;
}
/*
*
*/
int main() {
int n1, n2, n3;
set<int> list, n1Ar, n2Ar, n3Ar;
set<int>::iterator it;
scanf("%d", &n1);
scanf("%d", &n2);
scanf("%d", &n3);
int val = 0;
// Getting lists of voters
for (unsigned i = 0; i < n1; i++) {
cin >> val;
n1Ar.insert(val);
}
for (unsigned i = 0; i < n2; i++) {
cin >> val;
n2Ar.insert(val);
}
for (unsigned i = 0; i < n3; i++) {
cin >> val;
n3Ar.insert(val);
}
// Processing lists
for (set<int>::iterator i = n1Ar.begin(); i != n1Ar.end(); ++i) {
it = n2Ar.find(*i);
if (it != n2Ar.end()) {
list.insert(*i);
n1Ar.erase(i);
n2Ar.erase(it);
} else {
it = n3Ar.find(*i);
if (it != n3Ar.end()) {
list.insert(*i);
n1Ar.erase(i);
n3Ar.erase(it);
}
}
}
// Outputting the final list
cout << list.size() << endl;
for_each(list.begin(), list.end(), outputSet);
return 0;
}
我希望你能帮助我理解我在这里做错了什么。我只是从 C++ 开始。