angular - ngrx getWithQuery() 中的默认参数

Question

我想知道如何发送已经存在的默认数据getWithQuery()，如下所示：

@Injectable({providedIn: 'root'})
export class CompaniesDataService extends DefaultDataService<Company> {
    private readonly _URL: string = '/api/companies';
    private readonly _DEFAULT_QUERIES: QueryParams = {top: '0', limit: '10', order: "name"};

    constructor(http: HttpClient, httpUrlGenerator: HttpUrlGenerator) {
        super('Company', http, httpUrlGenerator);
    }

    getWithQuery(queryParams: QueryParams | string = this._DEFAULT_QUERIES): Observable<Company[]> {
        return this.http
            .post<FmsHttpResponse<Company>>(`${this._URL}/search`, queryParams)
            .pipe(map(response => response.content));
    }
}

我的意思this._DEFAULT_QUERIES是默认传递queryParams。getWithQuery()

当我像这样使用解析器添加功能时：

    return this.companyEntityService.getWithQuery()
      .pipe(tap(() => this.companyEntityService.setLoaded(true)));

我得到错误：Expected 1-2 arguments, but got 0.。

任何想法？我想补充一点，我是一个新手 ngrx 程序员，也许这是一个简单的问题，我找不到答案。

Answer 1

为什么你必须发送已经在类中的东西作为参数？为什么不做这样的事情：

 getWithQuery(queryParams: QueryParams | undefined): Observable<Company[]> {
       if(queryParams === undefined){
           queryParams = this._DEFAULT_QUERIES;
       }
        return this.http
            .post<FmsHttpResponse<Company>>(`${this._URL}/search`, queryParams)
            .pipe(map(response => response.content));
    }