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使用：Python 2.4

目前，我有一个嵌套的 for 循环，它遍历 2 个列表并根据两个列表中存在的两个元素进行匹配。一旦找到匹配项，它就会从 r120Final 列表中取出元素，并将其放入一个名为“r120Delta”的新列表中：

for r120item in r120Final:
    for spectraItem in spectraFinal:
    if(str(spectraItem[0]) == r120item[2].strip()) and (str(spectraItem[25]) == r120item[10]):
        r120Delta.append(r120item)
        break

问题是这太慢了，而且列表没有那么深。R120 约 64,000 行，Spectra 约 150,000 行。

r120Final 列表是一个嵌套数组，它看起来像这样：

r120Final[0] = [['xxx','xxx','12345','xxx','xxx','xxx','xxx','xxx','xxx','xxx','234567']]
...
r120Final[n] = [['xxx','xxx','99999','xxx','xxx','xxx','xxx','xxx','xxx','xxx','678901']]

SpectrumFinal 列表本质上是相同的，一个嵌套数组，它看起来像这样：

spectraFinal[0] = [['12345','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','234567']]
...
spectraFinal[0] = [['99999','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','xxx','678901']]

最后，“r120Delta”的原因是这样我就可以在 r120Final 和 r120Delta 之间进行列表差异，并检索不匹配的 r120 数据元素。这是我为这个任务定义的函数，而且速度很慢：

def listDiff( diffList, completeList ):
    returnList = []
        for completeItem in completeList:
            if not completeItem  in diffList:
                returnList.append(completeItem)
    return returnList

基本上，我精通 Python，但绝不是专家。我正在寻找一些专家来告诉我如何加快速度。任何帮助表示赞赏！

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1 回答 1

2 
spectra_set = set((str(spectraItem[0]), str(spectraItem[25])) for spectraItem in spectraFinal)

returnList = []
for r120item in r120Final:
    if (r120item[2].strip(), r120item[10]) not in spectra_set:
       returnList.append(r120item)

这会将所有不匹配的项目添加到returnList.

你可以在一行中完成（如果你真的想要的话）

returnList = [r120item for r120item in r120Final 
                 if (r120item[2].strip(), r120item[10]) not in 
                     set((str(spectraItem[0]), str(spectraItem[25])) 
                         for spectraItem in spectraFinal)]

如果您需要完整的spectraItem：

spectra_dict = dict(((str(spectraItem[0]), str(spectraItem[25])), spectraItem) for spectraItem in spectraFinal)
returnList = []
for r120item in r120Final:
    key = (r120item[2].strip(), r120item[10])
    if key not in spectra_dict:
        returnList.append(r120item)
    else:
        return_item = some_function_of(r120item, spectra_dict[key])
        returnList.append(return_item)
于 2011-08-04T17:32:41.677 回答