1

我编写了一个脚本，用 rb-appscript 将 PSD 导出为 PNG。这很好，花花公子，但我似乎无法在 py-appscript 中完成它。

这是红宝石代码：

#!/usr/bin/env ruby

require 'rubygems'
require 'optparse'
require 'appscript'

ps = Appscript.app('Adobe Photoshop CS5.app')
finder = Appscript.app("Finder.app")

path = "/Users/nbaker/Desktop/"
ps.activate
ps.open(MacTypes::Alias.path("#{path}guy.psd"))

layerSets = ps.current_document.layer_sets.get

# iterate through all layers and hide them
ps.current_document.layers.get.each do |layer|
    layer.visible.set false 
end 

layerSets.each do |layerSet|
    layerSet.visible.set false
end

# iterate through all layerSets, make them visible, and create a PNG for them
layerSets.each do |layerSet|
    name = layerSet.name.get
    layerSet.visible.set true
    ps.current_document.get.export(:in => "#{path}#{name}.png", :as => :save_for_web, 
                             :with_options => {:web_format => :PNG, :png_eight => false})
    layerSet.visible.set false
end

这是显然不等价的python代码：

from appscript import *
from mactypes import *

# fire up photoshop
ps = app("Adobe Photoshop CS5.app")
ps.activate()

# open the file for editing
path = "/Users/nbaker/Desktop/"
f = Alias(path + "guy.psd")
ps.open(f)

layerSets = ps.current_document.layer_sets()

# iterate through all layers and hide them
for layer in ps.current_document.layers():
    layer.visible.set(False)  

#... and layerSets  
for layerSet in layerSets:  
    layerSet.visible.set(False)

# iterate through all layerSets, make them visible, and create a PNG for them
for layerSet in layerSets:
    name = layerSet.name()
    layerSet.Visible = True
    ps.current_document.get().export(in_=Alias(path + name + ".png"), as_=k.save_for_web,
                 with_options={"web_format":k.PNG, "png_eight":False})

python 脚本中唯一不起作用的部分是保存。我在尝试不同的导出选项和东西时遇到了各种各样的错误：

连接无效... 发生一般 Photoshop 错误。此功能在此版本的 Photoshop 中可能不可用...无法将某些数据转换为预期类型...

我可以只使用 ruby​​ 脚本，但我们所有的其他脚本都在 python 中，所以能够在 python 中完成它会很好。提前感谢互联网。

4

1 回答 1

1

伯特，

我想我有一个解决方案给你——尽管几个月后。请注意，我是 Python 新手，所以这绝不是优雅的。

当我试用你的脚本时，它也一直在为我崩溃。但是，通过删除导出调用中的“别名”，似乎没问题：

from appscript import *
from mactypes import *

# fire up photoshop
ps = app("Adobe Photoshop CS5.1.app")
ps.activate()

# open the file for editing
path = "/Users/ian/Desktop/"
f = Alias(path + "Screen Shot 2011-10-13 at 11.48.51 AM.psd")
ps.open(f)

layerSets = ps.current_document.layer_sets()

# no need to iterate
ps.current_document.layers.visible.set(False)
ps.current_document.layer_sets.visible.set(False)

# iterate through all layerSets, make them visible, and create a PNG for them
for l in layerSets:
    name = l.name()
    # print l.name()
    l.visible.set(True)
    # make its layers visible too
    l.layers.visible.set(True)
    # f = open(path + name + ".png", "w").close()

    ps.current_document.get().export(in_=(path + name + ".png"), as_=k.save_for_web,
                 with_options={"web_format":k.PNG, "png_eight":False})

我也注意到，您遍历所有层以切换它们的可见性。实际上，您可以一次向它们发出所有命令——我的理解是它更快，因为它不必继续发出 Apple 事件。

我的脚本的逻辑不正确（关于打开和关闭图层），但你明白了。

伊恩

于 2011-12-07T04:31:13.883 回答