336

我创建了以下函数来检查连接状态：

private void checkConnectionStatus() {
    HttpClient httpClient = new DefaultHttpClient();

    try {
      String url = "http://xxx.xxx.xxx.xxx:8000/GaitLink/"
                   + strSessionString + "/ConnectionStatus";
      Log.d("phobos", "performing get " + url);
      HttpGet method = new HttpGet(new URI(url));
      HttpResponse response = httpClient.execute(method);

      if (response != null) {
        String result = getResponse(response.getEntity());
        ...

当我关闭服务器以测试执行时，在线等待很长时间

HttpResponse response = httpClient.execute(method);

有谁知道如何设置超时以避免等待太久？

谢谢！

4

10 回答 10

625

在我的示例中，设置了两个超时。连接超时抛出java.net.SocketTimeoutException: Socket is not connected和套接字超时java.net.SocketTimeoutException: The operation timed out。

HttpGet httpGet = new HttpGet(url);
HttpParams httpParameters = new BasicHttpParams();
// Set the timeout in milliseconds until a connection is established.
// The default value is zero, that means the timeout is not used. 
int timeoutConnection = 3000;
HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
// Set the default socket timeout (SO_TIMEOUT) 
// in milliseconds which is the timeout for waiting for data.
int timeoutSocket = 5000;
HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);

DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
HttpResponse response = httpClient.execute(httpGet);

如果您想设置任何现有 HTTPClient 的参数（例如 DefaultHttpClient 或 AndroidHttpClient），您可以使用函数setParams()。

httpClient.setParams(httpParameters);
于 2009-10-14T09:39:11.340 回答
13

要在客户端上设置设置：

AndroidHttpClient client = AndroidHttpClient.newInstance("Awesome User Agent V/1.0");
HttpConnectionParams.setConnectionTimeout(client.getParams(), 3000);
HttpConnectionParams.setSoTimeout(client.getParams(), 5000);

我已经在 J​​ellyBean 上成功使用了它，但也应该适用于旧平台....

高温高压

于 2012-08-29T15:56:34.920 回答
8

如果您使用的是 Jakarta 的http 客户端库，那么您可以执行以下操作：

        HttpClient client = new HttpClient();
        client.getParams().setParameter(HttpClientParams.CONNECTION_MANAGER_TIMEOUT, new Long(5000));
        client.getParams().setParameter(HttpClientParams.SO_TIMEOUT, new Integer(5000));
        GetMethod method = new GetMethod("http://www.yoururl.com");
        method.getParams().setParameter(HttpMethodParams.SO_TIMEOUT, new Integer(5000));
        method.getParams().setParameter(HttpMethodParams.RETRY_HANDLER,
        int statuscode = client.executeMethod(method);
于 2009-03-29T02:23:58.343 回答
7

如果您使用的是默认的 http 客户端，以下是使用默认 http 参数的方法：

HttpClient client = new DefaultHttpClient();
HttpParams params = client.getParams();
HttpConnectionParams.setConnectionTimeout(params, 3000);
HttpConnectionParams.setSoTimeout(params, 3000);

原始信用转到http://www.jayway.com/2009/03/17/configuring-timeout-with-apache-httpclient-40/

于 2015-01-15T02:57:55.550 回答
5

对于那些说@kuester2000的答案不起作用的人，请注意HTTP请求，首先尝试通过DNS请求找到主机IP，然后向服务器发出实际的HTTP请求，因此您可能还需要设置一个DNS 请求超时。

如果您的代码在 DNS 请求没有超时的情况下工作，那是因为您能够访问 DNS 服务器，或者您正在访问 Android DNS 缓存。顺便说一句，您可以通过重新启动设备来清除此缓存。

此代码扩展了原始答案以包含具有自定义超时的手动 DNS 查找：

//Our objective
String sURL = "http://www.google.com/";
int DNSTimeout = 1000;
int HTTPTimeout = 2000;

//Get the IP of the Host
URL url= null;
try {
     url = ResolveHostIP(sURL,DNSTimeout);
} catch (MalformedURLException e) {
    Log.d("INFO",e.getMessage());
}

if(url==null){
    //the DNS lookup timed out or failed.
}

//Build the request parameters
HttpParams params = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(params, HTTPTimeout);
HttpConnectionParams.setSoTimeout(params, HTTPTimeout);

DefaultHttpClient client = new DefaultHttpClient(params);

HttpResponse httpResponse;
String text;
try {
    //Execute the request (here it blocks the execution until finished or a timeout)
    httpResponse = client.execute(new HttpGet(url.toString()));
} catch (IOException e) {
    //If you hit this probably the connection timed out
    Log.d("INFO",e.getMessage());
}

//If you get here everything went OK so check response code, body or whatever

使用方法：

//Run the DNS lookup manually to be able to time it out.
public static URL ResolveHostIP (String sURL, int timeout) throws MalformedURLException {
    URL url= new URL(sURL);
    //Resolve the host IP on a new thread
    DNSResolver dnsRes = new DNSResolver(url.getHost());
    Thread t = new Thread(dnsRes);
    t.start();
    //Join the thread for some time
    try {
        t.join(timeout);
    } catch (InterruptedException e) {
        Log.d("DEBUG", "DNS lookup interrupted");
        return null;
    }

    //get the IP of the host
    InetAddress inetAddr = dnsRes.get();
    if(inetAddr==null) {
        Log.d("DEBUG", "DNS timed out.");
        return null;
    }

    //rebuild the URL with the IP and return it
    Log.d("DEBUG", "DNS solved.");
    return new URL(url.getProtocol(),inetAddr.getHostAddress(),url.getPort(),url.getFile());
}

这门课来自这篇博文。如果你会使用它，去检查一下备注。

public static class DNSResolver implements Runnable {
    private String domain;
    private InetAddress inetAddr;

    public DNSResolver(String domain) {
        this.domain = domain;
    }

    public void run() {
        try {
            InetAddress addr = InetAddress.getByName(domain);
            set(addr);
        } catch (UnknownHostException e) {
        }
    }

    public synchronized void set(InetAddress inetAddr) {
        this.inetAddr = inetAddr;
    }
    public synchronized InetAddress get() {
        return inetAddr;
    }
}
于 2015-07-26T23:54:31.353 回答
3

一个选项是使用来自 Square的OkHttp客户端。

添加库依赖

在 build.gradle 中，包含以下行：

compile 'com.squareup.okhttp:okhttp:x.x.x'

x.x.x所需的库版本在哪里。

设置客户端

例如，如果您想设置 60 秒的超时，请执行以下操作：

final OkHttpClient okHttpClient = new OkHttpClient();
okHttpClient.setReadTimeout(60, TimeUnit.SECONDS);
okHttpClient.setConnectTimeout(60, TimeUnit.SECONDS);

ps：如果你的 minSdkVersion 大于 8，可以使用TimeUnit.MINUTES. 因此，您可以简单地使用：

okHttpClient.setReadTimeout(1, TimeUnit.MINUTES);
okHttpClient.setConnectTimeout(1, TimeUnit.MINUTES);

有关单位的更多详细信息，请参阅TimeUnit。

于 2015-08-07T04:15:15.970 回答
1 
HttpParams httpParameters = new BasicHttpParams();
            HttpProtocolParams.setVersion(httpParameters, HttpVersion.HTTP_1_1);
            HttpProtocolParams.setContentCharset(httpParameters,
                    HTTP.DEFAULT_CONTENT_CHARSET);
            HttpProtocolParams.setUseExpectContinue(httpParameters, true);

            // Set the timeout in milliseconds until a connection is
            // established.
            // The default value is zero, that means the timeout is not used.
            int timeoutConnection = 35 * 1000;
            HttpConnectionParams.setConnectionTimeout(httpParameters,
                    timeoutConnection);
            // Set the default socket timeout (SO_TIMEOUT)
            // in milliseconds which is the timeout for waiting for data.
            int timeoutSocket = 30 * 1000;
            HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
于 2014-07-03T12:38:05.287 回答
1

如果您使用的是，请按此处HttpURLConnection所述调用：setConnectTimeout()

URL url = new URL(myurl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setConnectTimeout(CONNECT_TIMEOUT);
于 2014-09-04T22:50:35.627 回答
1

您可以通过 Httpclient-android-4.3.5 的方式创建 HttpClient 实例，它可以正常工作。

 SSLContext sslContext = SSLContexts.createSystemDefault();
        SSLConnectionSocketFactory sslsf = new SSLConnectionSocketFactory(
                sslContext,
                SSLConnectionSocketFactory.STRICT_HOSTNAME_VERIFIER);
                RequestConfig.Builder requestConfigBuilder = RequestConfig.custom().setCircularRedirectsAllowed(false).setConnectionRequestTimeout(30*1000).setConnectTimeout(30 * 1000).setMaxRedirects(10).setSocketTimeout(60 * 1000);
        CloseableHttpClient hc = HttpClients.custom().setSSLSocketFactory(sslsf).setDefaultRequestConfig(requestConfigBuilder.build()).build();
于 2014-11-24T07:37:28.437 回答
0 
public boolean isInternetWorking(){
    try {
        int timeOut = 5000;
        Socket socket = new Socket();
        SocketAddress socketAddress = new InetSocketAddress("8.8.8.8",53);
        socket.connect(socketAddress,timeOut);
        socket.close();
        return true;
    } catch (IOException e) {
        //silent
    }
    return false;
}
于 2018-02-27T06:28:24.787 回答