目前正在尝试实现一种在 Python 应用程序上接收陷阱的方法。我的设备直接将他的 snmpV2 陷阱发送到我的机器(测试与其他软件一起使用),但 PySNMP 似乎没有接收到它们。我直接使用文档中的示例代码。我的设备不安全,不需要任何密码或证书。社区是公开的。
我尝试将绑定端口更改为直接使用 0.0.0.0、127.0.0.1 和我的计算机的 IP。依然没有。
这是我正在使用的代码:
def v2cv1CallBackFunc(snmpEngine, stateReference, contextEngineId, contextName,
varBinds, cbCtx):
transportDomain, transportAddress = snmpEngine.msgAndPduDsp.getTransportInfo(stateReference)
print(transportDomain, transportAddress)
# Get an execution context...
execContext = snmpEngine.observer.getExecutionContext(
'rfc3412.receiveMessage:request'
)
# ... and use inner SNMP engine data to figure out peer address
print('Notification from %s, ContextEngineId "%s", ContextName "%s"'
%('@'.join([str(x) for x in execContext['transportAddress']]),
contextEngineId.prettyPrint(), contextName.prettyPrint()))
for name, val in varBinds:
print('%s = %s' % (name.prettyPrint(), val.prettyPrint()))
def runSNMP():
# Create SNMP engine with autogenernated engineID and pre-bound
# to socket transport dispatcher
snmpEngine = engine.SnmpEngine()
# SNMPv1/2c setup
# SecurityName <-> CommunityName mapping
config.addV1System(snmpEngine, 'my-area', "public")
# Specify security settings per SecurityName (SNMPv2c -> 1)
config.addTargetParams(snmpEngine, 'my-creds', 'my-area', 'noAuthNoPriv', 1)
# Transport setup
# UDP over IPv4, first listening interface/port
config.addSocketTransport(
snmpEngine,
udp.domainName + (1, ),
udp.UdpSocketTransport().openServerMode(('127.0.0.1', 162))
)
# Register SNMP Application at the SNMP engine
ntfrcv.NotificationReceiver(snmpEngine, v2cv1CallBackFunc)
snmpEngine.transportDispatcher.jobStarted(1) # this job would never finish
# Run I/O dispatcher which would receive queries and send confirmations
try:
snmpEngine.transportDispatcher.runDispatcher()
except:
snmpEngine.transportDispatcher.closeDispatcher()
raise```