9

我有 2 个日期，比如 2011 年 3 月 28 日和 2011 年 6 月 29 日。我需要一个 sql 查询来显示这两个日期之间的月份，包括包含日期的月份，即。六月、五月、四月和三月。

4

6 回答 6

22

像这样的东西

SQL> ed
Wrote file afiedt.buf

    select to_char( add_months( start_date, level-1 ), 'fmMonth' )
      from (select date '2011-03-30' start_date,
                   date '2011-06-29' end_date
              from dual)
     connect by level <= months_between(
                           trunc(end_date,'MM'),
                           trunc(start_date,'MM') )
  *                      + 1
SQL> /

TO_CHAR(ADD_MONTHS(START_DATE,LEVEL-
------------------------------------
March
April
May
June

应该管用。

于 2011-08-03T13:52:12.193 回答
2

将添加此解决方案只是因为我认为它比其他解决方案更清洁：

SELECT ADD_MONTHS(TRUNC(TO_DATE('28-Mar-2011', 'DD-MON-YYYY'), 'MON'), ROWNUM - 1) date_out
FROM   DUAL
CONNECT BY ADD_MONTHS(TRUNC(TO_DATE('28-Mar-2011', 'DD-MON-YYYY'), 'MON'), ROWNUM - 1)
    <= TRUNC(TO_DATE('29-Jun-2011', 'DD-MON-YYYY'), 'MON')
于 2013-07-23T16:30:20.343 回答
1

您可以使用函数MONTHS_BETWEEN

SELECT MOD( TRUNC( MONTHS_BETWEEN( '2011-07-29', '2011-03-28' ) ), 12 ) as MONTHS
FROM DUAL

输出

    MONTHS
----------
         4
于 2011-08-03T13:18:14.257 回答
1

几天前我需要一个答案。我找到了另一个我更喜欢的解决方案：

select to_char(which_month, 'Mon-yyyy') month
from
(
    select
        add_months(to_date(:start_date,'mm-yyyy'), rownum-1) which_month
    from
        all_objects
    where
        rownum <= months_between(to_date(:end_date,'mm-yyyy'), add_months(to_date(:start_date,'mm-yyyy'), -1))
    order by
        which_month
)

你当然可以使用任何你想要的格式。我“联合”并总结了另一组，这样即使他们没有结果，我也能得到月份。

于 2012-09-21T14:30:23.343 回答
0 
SELECT MIN (to_date((TO_CHAR (Actual_Date, 'DD-MM-RRRR')),'dd-mm-rrrr')) F_DATE,
         MAX (to_date((TO_CHAR (Actual_Date, 'DD-MM-RRRR')),'dd-mm-rrrr')) T_DATE,
         TO_CHAR (Actual_Date, 'MM-RRRR') TRX_MONTH     
    FROM (    SELECT TRUNC (TO_DATE (:P_FDATE, 'dd-mm-rrrr')) + LEVEL - 1
                        Actual_Date
                FROM (SELECT TRUNC (TO_DATE (:P_FDATE, 'dd-mm-rrrr'), 'MM') - 1
                                AS dt
                        FROM DUAL)
          CONNECT BY LEVEL <=
                        (  TO_DATE (:P_TDATE, 'dd-mm-rrrr')
                         - TRUNC (TO_DATE (:P_FDATE, 'dd-mm-rrrr'))
                         + 1))
GROUP BY TO_CHAR (Actual_Date, 'MM-RRRR')
ORDER BY 1
于 2016-12-24T09:19:11.940 回答
0 
     declare 
        v_date_from_first_day date;
        v_date_to_last_day date;
        v_month_name varchar2(10);
        v_month_number number;
        v_year_number number;
        v_month_diff number;
        begin
          v_date_to_last_day := to_date('31.12.2018'); 
          v_date_from_first_day := to_date('01.01.2018');

          select months_between(v_date_to_last_day,v_date_from_first_day) as diff into v_month_diff from dual;

          for i in 1..round(v_month_diff, 2) loop
          select 
          to_char(trunc(add_months(v_date_to_last_day - months_between(v_date_from_first_day, v_date_to_last_day), -i)), 'fmMonth') as month_nm,
          to_char(trunc(add_months(v_date_to_last_day - months_between(v_date_from_first_day, v_date_to_last_day), -i)), 'MM') as month_num,
          to_char(trunc(add_months(v_date_to_last_day - months_between(v_date_from_first_day, v_date_to_last_day), -i)), 'YYYY') as year_num
          into v_month_name, v_month_number, v_year_number
          from dual;

          dbms_output.put_line(v_month_number || '/' || v_year_number);
dbms_output.put_line(v_month_name || '/' || v_year_number);
          end loop;
        end;

        Output: 
        12/2018
        11/2018
        10/2018
        9/2018
        8/2018
        7/2018
        6/2018
        5/2018
        4/2018
        3/2018
        2/2018
        1/2018

在这里，月份名称是克罗地亚语

Prosinac/2018
Studeni/2018
Listopad/2018
Rujan/2018
Kolovoz/2018
Srpanj/2018
Lipanj/2018
Svibanj/2018
Travanj/2018
Ožujak/2018
Veljača/2018
Siječanj/2018
于 2019-01-15T12:09:40.160 回答