4

从空白画布开始:

<canvas id='myCanvas' width='800' height='600'></canvas>

然后初始化该画布:

  function init_canvas(){
    var canvas = document.getElementById('myCanvas');
    context = canvas.getContext('2d');
    context.lineCap = 'round';
    // fill it with white background
    context.save();
    context.fillStyle = '#fff';
    context.fillRect(0, 0, context.canvas.width, context.canvas.height);
    context.restore();
    return;
  }

然后在画布上画一堆。

然后尝试在后端使用 ajax 和 PHP 将其保存到服务器。

在客户端:

var img = canvas.toDataURL('image/png');
// strip the leading garbage.
img.substr(img.indexOf(',')+1).toString();

将生成的字符串(base64 编码的 png)直接发送到 PHP 和 base64_decode() 字符串...图像始终是正确的大小,但上面没有任何绘图 - 只是一个透明图像。这似乎不是 PHP 中的 base64_decode() 的问题,它似乎是一个安全问题。它在 Firefox 4 和最新的 Chrome 中都失败了。

将生成的 png 图像转储到带有“image/png”标头的 firefox 会在错误控制台中产生:

Error: Image corrupt or truncated: http://somewhere.com/showimage.php
Source file: http://somewhere.com/showimage.php

但是......图像没有损坏或被截断,除非 toDataURL() 到处都被破坏,因为 php 的东西只是 base64_decode() toDataURL() 的结果。

有任何想法吗?

谢谢!

4

4 回答 4

7

您是否在 PHP 文档中看到此评论base64_decode

如果要保存从 Javascript canvas.toDataURL() 函数派生的数据,则必须将空白转换为加号。如果你不这样做,解码的数据就会损坏:

<?php
  $encodedData = str_replace(' ','+',$encodedData);
  $decocedData = base64_decode($encodedData);
?>
于 2011-08-04T00:28:36.743 回答
0

像我以前的问题吗?

也许你可以检查一下

jQuery 和 Canvas.toDataURL

安全错误”代码:“在带有 Canvas.toDataURL 的 Firefox 上为 1000

于 2011-08-03T11:06:58.510 回答
0

这可以正常工作而不会返回空白图像。

保存图像.php

 <?php 
        $result = array();  
        $encodedData = explode("," , $_POST['imgData'])[1];
        $encodedData = str_replace(' ','+',$encodedData);
        $decocedData = base64_decode($encodedData); 
        //Location to where you want to save image
        $NewFileName = './photos/'.$_POST['imgName'].'.jpg';
        file_put_contents($NewFileName,$decocedData);
        $result['status'] = 1;
        $result['saveImage'] = $NewFileName;
        echo json_encode($result);
    ?>

脚本.js

<script>
//This post the data to server on fly

function saveImage(canvasData,FileName) {
  var xmlHttpReq = false;

  if (window.XMLHttpRequest) {
    ajax = new XMLHttpRequest();
  }
  else if (window.ActiveXObject) {
    ajax = new ActiveXObject("Microsoft.XMLHTTP");
  }

  ajax.open("POST", "saveImage.php", false);
  ajax.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
  ajax.onreadystatechange = function() {

    if (this.readyState == 4 && this.status == 200) {
        var rawArr = JSON.parse(this.responseText);
        var ImagePreviewer= document.getElementById("ImagePreviewer");
    ImagePreviewer.src=rawArr.saveImage;
    //console.log(rawArr.saveImage);
    }

  }
  ajax.send("imgData=" + canvasData+"&imgName=" + FileName);
}
// Call this with button click or whatever you want 
function saveJPG(filename) {
//do other logic here
var dataURL = TheCanvas.toDataURL("image/jpg");
    saveImage(dataURL,filename);
}
<script>
于 2019-09-08T22:21:57.297 回答
-1

在 JavaScript 中,从canvas.toDataURL()那些浏览器上发送结果,而不是使用默认类型“image/png”支持此方法。

var imageInfo = canvas.toDataURL();

直接创建png文件的方法:

<?php
$imageInfo = imageInfoFromBrowser(); // Your method to get the data
$image = fopen($imageInfo, 'r');
file_put_contents("fileName.png", $image);
fclose($image);
?>

我在 PHP 5.3 中有这个工作,对于其他版本,请检查。

用于在 PHP 上测试的图像数据示例。

$imageDataInfoSample = "data:image/png;base64,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"
于 2012-01-13T09:29:45.417 回答