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我正在尝试将 SQL Server 结果转换为双重嵌套的 JSON 格式。

源 SQL Server 表：

ID 姓名 程序 类型 部分 导向器 项目 高级经理 PCM 承包商 成本客户
123 美国广播公司 qw 秋 dd 好久不见 hkhjk fghfgf 关注 呸呸呸 呸呸呸
456 结衣 gdfgf 生长激素 jkjlkll uiop 呸呸呸 射频识别 ujmk rfvtg 蛋黄酱

转换为双重 JSON，如下所示：

[
    [
    {"key":"ID","value":"123"},
    {"key":"Name","value":"abc"},
    {"key":"Program","value":"qew"},
    {"key":"Type","value":"tyu"},
    {"key":"Section","value":"dd"},
    {"key":"Director","value":"ghghjg"},
    {"key":"Project","value":"hkhjk"},
    {"key":"Sr Manager","value":"fghfgf"},
    {"key":"PCM","value":"gnhghj"},
    {"key":"Contractor","value":"gghgh"},
    {"key":"Cost Client","value":"gghhg"}
    ],
    [
    {"key":"ID","value":"456"},
    {"key":"Name","value":"yui"},
    {"key":"Program","value":"gdffgf"},
    {"key":"Type","value":"ghgfjhjhj"},
    {"key":"Section","value":"jkjlkll"},
    {"key":"Director","value":"uiop"},
    {"key":"Project","value":"rtyuui"},
    {"key":"Sr Manager","value":"rfv"},
    {"key":"PCM","value":"ujmk"},
    {"key":"Contractor","value":"rfvtg"},
    {"key":"Cost Client","value":"efgg"}
    ]
]

任何帮助将不胜感激。

编辑：我从重写“FOR JSON AUTO”开始，这样我就可以以某种方式添加“Key”“Value”文本。但是因为我的表在列名中有空格，所以 FOR XML PATH('') 按照 FOR XML 错误的要求给出了无效的 XML 标识符。那是我想到接受社区帮助的时候。

Create PROCEDURE [dbo].[GetSQLtoJSON] @TableName VARCHAR(255)
    AS
    BEGIN
        IF OBJECT_ID(@TableName) IS NULL
            BEGIN
                SELECT Json = '';
                RETURN
            END;
    
    
        DECLARE @SQL NVARCHAR(MAX) = N'SELECT * INTO ##T ' + 
                                    'FROM ' + @TableName;
    
        EXECUTE SP_EXECUTESQL @SQL;
    
        DECLARE @X NVARCHAR(MAX) = '[' + (SELECT * FROM ##T FOR XML PATH('')) + ']';
    
    
        SELECT  @X = REPLACE(@X, '<' + Name + '>', 
                        CASE WHEN ROW_NUMBER() OVER(ORDER BY Column_ID) = 1 THEN '{'
                             ELSE '' END + Name + ':'),
                @X = REPLACE(@X, '</' + Name + '>', ','),
                @X = REPLACE(@X, ',{', '}, {'),
                @X = REPLACE(@X, ',]', '}]')
        FROM    sys.columns
        WHERE   [Object_ID] = OBJECT_ID(@TableName)
        ORDER BY Column_ID;
    
        DROP TABLE ##T;
    
        SELECT  Json = @X;
    
    END

样本数据：

CREATE TABLE [dbo].[Test1](
    [ID] [int] IDENTITY(1,1) NOT NULL,
    [Col1] [int] NOT NULL,
    [Col 2] varchar(50)
) ON [PRIMARY]
GO
SET IDENTITY_INSERT [dbo].[Test1] ON 
GO
INSERT [dbo].[Test1] ([ID], [Col1], [Col 2]) VALUES (1, 0,'ABCD')
GO
INSERT [dbo].[Test1] ([ID], [Col1] ,[Col 2]) VALUES (2, 1, 'POIU')

GO
SET IDENTITY_INSERT [dbo].[Test1] OFF
GO
4

2 回答 2

1

您可以使用以下代码：

  • 在 aAPPLY中，将列取消旋转为键/值对...
  • ...并聚合使用FOR JSON PATH
  • 用于STRING_AGG进行另一个聚合。
SELECT '[' + STRING_AGG(CAST(v.json AS nvarchar(max)), ',') + ']'
FROM T
CROSS APPLY (
    SELECT *
    FROM (VALUES
        ('ID', CAST(ID AS nvarchar(100))),
        ('Name', Name),
        ('Program', Program),
        ('Type', [Type]),
        ('Section', Section),
        ('Director', Director),
        ('Project', Project),
        ('Sr Manager', [Sr Manager]),
        ('PCM', PCM),
        ('Contractor', Contractor),
        ('Cost Client', [Cost Client])
    ) v([key], value)
    FOR JSON PATH
) v(json)

db<>小提琴

你不能FOR JSON再次使用，因为那样你会得到["json": [{"key" : ...

于 2021-09-14T10:04:43.620 回答
0

首先检查这个链接你可以找到你想要的

格式-查询-结果-as-json-with-for-json-sql-server

但在你的情况下，你可以试试这个

 SELECT 
    ID,Name,Program,Type,Section,
    Director,Project,Sr,Manager,PCM,Contractor,Cost,Client
 FROM table  
 FOR JSON AUTO;

检查链接有更多的样本，所以它可以帮助你

于 2021-09-14T05:10:32.560 回答