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有没有什么方法可以在屏幕上获得最常用的颜色（或最亮的颜色？）作为环境光/显示器背光，而无需过多使用 CPU？有没有办法利用已经计算颜色的显卡（也许是 NVApi）来做到这一点？如果有，有没有办法在 python 的循环中导入该颜色？

我现有的代码有效，但使用了 CPU，这是我在玩更激烈的游戏时需要的。无论如何，这是我现有的代码：

from __future__ import print_function
import binascii
import struct
from PIL import Image
import numpy as np
import scipy
import scipy.misc
import scipy.cluster
import pyautogui
import requests
import json
import sys

class Main():
    def __init__(self):
        self.OnSwitch = True

        while True:
            if self.OnSwitch:
                self.average_image_color()
                self.ColorToLed()

    def average_image_color(self):
        NUM_CLUSTERS = 5

        im = pyautogui.screenshot()
        im = im.resize((150, 150))      # optional, to reduce time
        ar = np.asarray(im)
        shape = ar.shape
        ar = ar.reshape(np.product(shape[:2]), shape[2]).astype(float)
        codes, dist = scipy.cluster.vq.kmeans(ar, NUM_CLUSTERS)

        vecs, dist = scipy.cluster.vq.vq(ar, codes)         # assign codes
        counts, bins = np.histogram(vecs, len(codes))    # count occurrences

        index_max = np.argmax(counts)                    # find most frequent
        peak = codes[index_max]
        color = "#"+binascii.hexlify(bytearray(int(c) for c in peak)).decode('ascii')
        self.rgb = self.hex_to_rgb(color)
        print(self.rgb)

    def hex_to_rgb(self,value):
        value = value.lstrip('#')
        lv = len(value)
        return list(int(value[i:i + lv // 3], 16) for i in range(0, lv, lv // 3))

    def ColorToLed(self):
        shelly = requests.get("http://xxx.xxx.xxx.xx/settings/light/0")
        result = json.loads(shelly.content)
        if not result["ison"]:
            requests.get("http://xxx.xxx.xxx.xx/color/0?turn=on")
        requests.get("http://xxx.xxx.xxx.xx/color/0?red="+str(self.rgb[0])+"&&green="+str(self.rgb[1])+"&&blue="+str(self.rgb[2])+"&&gain=100&&white=0&&effect=0&&transition=0")


if __name__ == '__main__':
    print("init")
    Main()

xxx.xxx.xxx.xx 是我的 RGB LED 控制器的 IP 地址

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