javascript - 如何下载“懒惰”加载图像？ 我使用了 JavaScript 执行器并能够找到ImageElement，但是当我尝试提取 URL（用于下载 image.svg）时，我收到错误“NoSuchElementException”，下面是我的代码： ((JavascriptExecutor)driver).executeScript("window.open('h

Question

我使用了 JavaScript 执行器并能够找到ImageElement，但是当我尝试提取 URL（用于下载 image.svg）时，我收到错误“NoSuchElementException”，下面是我的代码：

((JavascriptExecutor)driver).executeScript("window.open('https://www.lambdatest.com/selenium-automation/','_blank');");                     
wait.until(webDriver -> ((JavascriptExecutor) webDriver).executeScript("return document.readyState").equals("complete"));         
WebDriverWait wait = new WebDriverWait(driver, Duration.ofSeconds(10));  
JavascriptExecutor js = (JavascriptExecutor) driver;   

By Image=By.xpath("//img[@title='Jenkins']");            
js.executeScript("window.scrollTo(0, document.body.scrollHeight)");           
      //  Below commented snippet is giving Error 
/*WebElement ImageElemnt =driver.findElement(Image); 
   String src = ImageElemnt.getAttribute("src");    
    System.out.println(src);*/



wait.ignoring(NoSuchElementException.class).until(ExpectedConditions.invisibilityOfElementLocated(Image))

Answer 1

问题说明：

您的代码的第一行是

((JavascriptExecutor)driver).executeScript("window.open('https://www.lambdatest.com/selenium-automation/','_blank');");  

这基本上意味着您正在尝试https://www.lambdatest.com/selenium-automation/在新选项卡中打开。Selenium 不知道，直到您告诉 Selenium 您现在必须切换到不同的选项卡才能进一步执行。

所以，你的代码行应该是这样的

((JavascriptExecutor)driver).executeScript("window.open('https://www.lambdatest.com/selenium-automation/','_blank');");  
ArrayList<String> tabs2 = new ArrayList<String> (driver.getWindowHandles());
driver.switchTo().window(tabs2.get(1));

更新 1：

((JavascriptExecutor) driver).executeScript("window.open('https://www.lambdatest.com/selenium-automation/','_blank');");
ArrayList<String> tabs2 = new ArrayList<String>(driver.getWindowHandles());
driver.switchTo().window(tabs2.get(1));
Thread.sleep(5000);
WebElement ele = wait.until(ExpectedConditions.elementToBeClickable(By.xpath("//img[@title='Jenkins']")))
js.executeScript("arguments[0].scrollIntoView(true);", ele);
String src = ele.getAttribute('src')
System.out.println(src);