我正在尝试汇总子公司的支出,包括所有没有任何递归函数的孙子公司。
我的数据集看起来类似于这种格式:
Parent A
- Child A.1 - $1,000
- Child A.2 - $2,000
- - Grandchild A.2.1 - $500
- - Grandchild A.2.2 - $750
- Child A.3 - $3,000
- Child A.4 - $4,000
Parent B
- Child B.1 - $11,000
- Child B.2 - $12,000
- - Grandchild B.2.1 - $1,500
- - Grandchild B.2.2 - $1,750
- Child B.3 - $13,000
- Child B.4 - $14,000
我想要做的是父 A 的子总和,所以结果会输出如下:
Child A.1 - $1,000
Child A.2 - $3,250
Child A.3 - $3,000
Child A.4 - $4,000
这是我的公司表的简化结构:
id
name
parent_id
lft
rght
这是我的支出表的简化结构:
id
company_id
amount
date
我知道如何仅列出父母 A 的每个孩子及其金额:
SELECT
`Company`.`name` AS `name`,
SUM(`Spend`.`amount`) AS `amount`
FROM
`spend_table` AS `Spend`
INNER JOIN companies_table AS `Company` ON `Spend`.`company_id` = `Company`.`id`
INNER JOIN companies_table AS `thisCompany` ON `Company`.`lft` BETWEEN `thisCompany`.`lft` AND `thisCompany`.`rght`
WHERE
`thisCompany`.`name` = 'Parent A'
GROUP BY
`Company`.`name`
这将输出:
Child A.1 - $1,000
Child A.2 - $2,000
Grandchild A.2.1 - $500
Grandchild A.2.2 - $750
Child A.3 - $3,000
Child A.4 - $4,000
我知道如何为父母 A 的每个孩子(不包括孙子)求和:
SELECT
`Company`.`name` AS `name`,
SUM(`Spend`.`amount`) AS `amount`
FROM
`spend_visibility2` AS `SpendVisibility`
`spend_table` AS `Spend`
INNER JOIN companies_table AS `Company` ON `Spend`.`company_id` = `Company`.`id`
INNER JOIN companies_table AS `thisCompany` ON `Company`.`lft` BETWEEN `thisCompany`.`lft` AND `thisCompany`.`rght`
WHERE
`thisCompany`.`name` = 'Parent A'
`Company`.`parent_id` = `thisCompany`.`id`
GROUP BY
`Company`.`name`
这将输出:
Child A.1 - $1,000
Child A.2 - $2,000
Child A.3 - $3,000
Child A.4 - $4,000
有人能帮我吗?我相信我需要一个子选择,但很难弄清楚。