我正在使用快速 API 来获取 LinkedIn 数据。这个特殊的 API 使用简单的 HTTPS GET 请求并返回 json。我正在写这是 Google App Script (Javascript) 并在运行测试时返回此错误。
function callLinkedInAPI () {
// https://rapidapi.com/iscraper/api/linkedin-profiles-and-company-data/ API website
// https://iscraper.io/docs APi Docs
var payload = {
"profile_id": "williamhgates",
"profile_type": "personal",
"contact_info": false
}
var headers = {
"contentType": "application/json",
"x-rapidapi-host": "linkedin-profiles-and-company-data.p.rapidapi.com",
"x-rapidapi-key": "76db3a1901mshd1518c9ce779bdep1c5920jsn3e0ec4853b66"
}
var url = `https://linkedin-profiles-and-company-data.p.rapidapi.com/api/v1/profile-details`
var requestOptions = {
'method': "POST",
'headers': headers,
'payload': payload,
'muteHttpExceptions': true,
'redirect': 'follow'
};
var response = UrlFetchApp.fetch(url, requestOptions);
var json = response.getContentText();
var data = JSON.parse(json);
console.log(data)
}
我在调用 api 时收到此错误
[ { msg: 'value is not a valid dict',
loc: [Object],
type: 'type_error.dict' } ]