java - OpenSAML 自定义属性值

Question

我正在尝试创建 SAML 响应。构成断言的属性之一称为地址，属性值需要是在 XSD 中定义的自定义类型。如何将自定义属性值类型添加到响应中？

Answer 1

如果您的属性值 XML 是字符串形式：

String yourXMLFragment = "...";

AttributeStatementBuilder attributeStatementBuilder = 
   (AttributeStatementBuilder) builderFactory.getBuilder(AttributeStatement.DEFAULT_ELEMENT_NAME);
AttributeStatement attributeStatement = attributeStatementBuilder.buildObject();

AttributeBuilder attributeBuilder = 
   (AttributeBuilder) builderFactory.getBuilder(Attribute.DEFAULT_ELEMENT_NAME);
Attribute attr = attributeBuilder.buildObject();
attr.setName("yourAttributeName");

XSAnyBuilder sb2 = (XSAnyBuilder) builderFactory.getBuilder(XSAny.TYPE_NAME);
XSAny attrAny = sb2.buildObject(AttributeValue.DEFAULT_ELEMENT_NAME, XSAny.TYPE_NAME);
attrAny.setTextContent(yourXMLFragment.trim());

attr.getAttributeValues().add(attrAny);
attributeStatement.getAttributes().add(attr);

Answer 2

实际上，以上并没有得出正确的结果。上面的示例只能用于创建带有文本内容而不是 xml 内容的 xsany（xml 内容被转义）。

因此，在挖掘 opensaml 源代码后，以下确实根据需要工作：

public XSAny createXSAny(Element dom)
{
XSAnyBuilder anyBuilder = (XSAnyBuilder) Configuration.getBuilderFactory().getBuilder(XSAny.TYPE_NAME);
    XSAny any = anyBuilder.buildObject(AttributeValue.DEFAULT_ELEMENT_NAME, XSAny.TYPE_NAME);
    // this builds only the root element not the whole dom
    XSAny xo=anyBuilder.buildObject(dom);
    // set/populate dom so whole dom gets into picture
    xo.setDOM(dom);
    any.getUnknownXMLObjects().add(xo);

  return any; 
}