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我有一个名为的表time_entries,列名为time_start.

我正在插入Carbon::now();它。存储在列中的数据2021-08-26 09:51:37显示blade.php相同的结果。

型号TimeEntry

namespace App\Models;

use Carbon\Carbon;
use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;

class TimeEntry extends Model
{
    use HasFactory;

    public function user()
    {
        return $this->belongsTo(User::class);
    }

    public function getTimeStartAttribute($value)
    {
        return Carbon::createFromFormat('H:i:s', $value)->TimeString();
    }
}

控制器:

namespace App\Http\Controllers\Admin;

use App\Http\Controllers\Controller;
use App\Models\TimeEntry;
use Illuminate\Http\Request;
use Illuminate\Support\Facades\Auth;

class AttendanceController extends Controller
{
    public function index()
    {
        $data = TimeEntry::where('user_id', Auth::user()->id)->paginate(2);

        return view('Admin.Attendance-History-page', compact('data'));
    }
}

刀片视图:

<tbody id="table_data">
    @foreach ($data as $punch)
        <tr>
            <td>{{ $punch->user->name }}</td>
            <td>{{ $punch->user->employee_id }}</td>
            <td>19 Feb 2019</td>
            <td>{{ $punch->time_start }} </td>
            <td>{{ $punch->time_end }}</td>
            <td>9 hrs</td>
            <td>
                <span class="badge bg-inverse-success">Perfect</span>
            </td>
            <td>0</td>
        </tr>
    @endforeach
</tbody>

我想知道如何将输出格式化为Blade 之2021-08-26 09:51:37类的东西?09:51:AM

谢谢您的帮助。

4

1 回答 1

1

date()使用 PHP方法有一个直接的解决方案。

{{ date('h:m A', strtotime($punch->time_start)) }}

这将输出09:51 AM

如果要输出,09:51:AM则只需在:之后添加m并删除空格,如下所示:

{{ date('h:m:A', strtotime($punch->time_start)) }}
于 2021-08-31T07:49:28.410 回答