我有以下课程:
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "type")
@JsonSubTypes(
JsonSubTypes.Type(value = Speech::class, name = "Speech"),
JsonSubTypes.Type(value = Audio::class, name = "Audio"),
)
sealed class AudioItem
data class Speech(val type: String = "Speech", val contentType: String = "SSML", val content: String) : AudioItem()
data class Audio(val type: String = "Audio", val source: String) : AudioItem()
当我尝试转换通用时ArrayList
:
到AudioItem
val audio: List<AudioItem> = ObjectMapper().findAndRegisterModules().convertValue(a)
我得到:
无法构造实例
AudioItem
(没有创建者,如默认构造函数,不存在):抽象类型要么需要映射到具体类型,要么具有自定义反序列化器,要么包含额外的类型信息