所以我制作了一个名称生成器/查找器，所以对于查找命令，我想在带有行号的 txt 文件中找到该名称！那么如何找到带有行号的名称？
line = 0
names = open(r"names.txt", "r")
name1 = names.readlines()
uname = input("Please enter the name you want to find: ")
for name in name1:
try:
print(name)
print(line)
if name == uname:
print(f"Found name: {name} \nLine No. {line + 1}")
else:
line = line + 1
except:
print("Unable to process")
但它似乎不起作用，除非你在文件中写下姓氏，否则它会起作用。那么可以提供任何帮助吗？
编辑：我找到了一种方法，如果您想为更多遇到问题的人回复，您可以回复！
尝试这个：
with open("names.txt", "r") as f:
file_contents = names.read().splitlines()
uname = input("Please enter the name you want to find: ")
for line, row in enumerate(file_contents):
if uname in row:
print('Name "{0}" found in line {1}'.format(uname, line))
你可以尝试这样的事情：
import re
search_name = input("Enter the name to find: ")
with open("names.txt", "r") as f:
for line, row in enumerate(f.read().splitlines()):
if re.findall('\\b'+search_name+'\\b', row, flags=re.IGNORECASE):
print('Name "{0}" found in line {1}'.format(search_name, line))
flags=re.IGNORECASE如果您希望搜索区分大小写，则可以删除该标志。
哟
if "namefilled" in name :
print("找到了")
如果你有 Python 3.4+，你可以使用 pathlib。很方便的图书馆。
此外，上下文管理很有用。
# Using pathlib
from pathlib import Path
# https://docs.python.org/3/library/fnmatch.html?highlight=fnmatch#module-fnmatch
import fnmatch
# Create Path() instance with path to text file (can be reference)
txt_file = Path(r"names.txt")
# Gather input
uname = input("Please enter the name you want to find: ")
# Set initial line variable
line = 0
find_all = False
# Use context maangement to auto-close file once complete.
with txt_file.open() as f:
for line in f.readlines():
# If python 3.8, you can use assignment operator (:=)
if match_list := fnmatch.filter(line, uname) is not None: # Doe not match substring.
number_of_names = len(match_list)
name_index = [i for i, element in enumerate(line.split()) for word in match_list if word == element]
print(f"""
{number_of_names} name{"s" if number_of_names > 0 else ""} found on line {line} at position {name_index}.
""".strip())
line += 1