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我想归档一些我从外部来源收到的文件。我将每个文件作为ByteArrayInputStream接收。最后，我希望我的方法能够创建 zip 存档并返回一个 byte[] 数组，以便稍后下载。我已经成功地做到了这一点，但最终结果是一个 ZipOutputStream 而不是我需要的 byte[] 数组。任何想法表示赞赏。谢谢！

       FileOutputStream fos = null;
       ZipOutputStream zipOut = null;

       try {
           fos = new FileOutputStream(archiveFileName.concat(ReportFormat.ZIP.getFileExtension()));
           zipOut = new ZipOutputStream(new BufferedOutputStream(fos));

           for (Map.Entry<?, ByteArrayInputStream> entry : mapInputStream.entrySet()) {
               String  fileFromInsiteArchiveName = (String) entry.getKey();
               ByteArrayInputStream inputStream = entry.getValue();

               ZipEntry zipEntry = new ZipEntry(fileFromInsiteArchiveName);
               zipOut.putNextEntry(zipEntry);
               byte[] tmp = new byte[4 * 1024];
               int size = 0;
               while ((size = inputStream.read(tmp)) != -1) {
                   zipOut.write(tmp, 0, size);
               }
               zipOut.flush();
               inputStream.close();
           }
           zipOut.close();

           return zipOut;

       } catch (FileNotFoundException e) {
           //handle this
       } catch (IOException e) {
           //handle this
       } finally {
           try {
               if (fos != null) fos.close();
           } catch (Exception ex) {
               //handlethis
           }
       }
       return zipOut;
   }
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1 回答 1

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复制到ByteArrayOutputStream然后执行baos.toByteArray()以获取您的byte[]

于 2021-08-19T10:51:24.403 回答