我在散点图上绘制了 Pandas DataFrame 的两列，我希望每个点都显示 DataFrame 的所有行值。我看过这篇文章，并尝试用mplcursors做类似的事情：
import pandas as pd
from datetime import date, datetime, time, timedelta
import numpy as np
import matplotlib.pyplot as plt
from mplcursors import cursor
df = pd.DataFrame()
df['datetime'] = pd.date_range(start='2016-01-01', end='2016-01-14', freq='30T')
#df = df.set_index('datetime')
df['x1'] = np.random.randint(-30, 30, size=len(df))
df['x2'] = np.random.randint(-30, 20, size=len(df))
df['x3'] = np.random.randint(-20, 30, size=len(df))
df['y1'] = np.random.randint(-100, 100, size=len(df))
df['y2'] = np.random.randint(-300, 200, size=len(df))
df['y3'] = np.random.randint(-200, 300, size=len(df))
def conditions(s):
if (s['y1'] > 20) or (s['y3'] < 0):
return 'group1'
elif (s['x3'] < 20):
return 'group2'
elif (s['x2'] == 0):
return 'group3'
else:
return 'group4'
df['category'] = df.apply(conditions, axis=1)
fig = plt.figure(figsize=(12,4))
ax1 = plt.subplot(121)
ax1.scatter(df.x1, df.y1, label='test1')
ax1.scatter(df.x2, df.y2, label='test2')
#cursor(hover=True)
ax1.set_xlabel('test1')
ax1.set_ylabel('test2')
ax1.legend(['test1','test2'])
cr1 = cursor(ax1,hover=True)
#ax1.annotation_names = df.columns.tolist()
cr1.connect("add", lambda x: x.annotation.set_text(df.columns.tolist()[x.target.index]))
ax2 = plt.subplot(122)
ax2.scatter(df.x1, df.y1, label='test1')
ax2.scatter(df.x3, df.y3, label='test3')
ax2.set_xlabel('test1')
ax2.set_ylabel('test3')
ax2.legend(['test1','test3'])
cr2 = cursor(ax2,hover=True)
#ax2.annotation_names = df.columns.tolist()
cr2.connect("add", lambda x: x.annotation.set_text(df.columns.tolist()[x.target.index]))
# save figure
import pickle
pickle.dump(fig, open('FigureObject.fig.pickle', 'wb'))
plt.show()
当我将鼠标悬停在一个点上时，我想看到一个包含（例如）的标签：
datetime = 2016-01-01 00:00:00
x1 = 1
x2 = -4
x3 = 22
y1 = -42
y2 = -219
y3 = -158
category = group1
但我收到这种类型的错误：
cr2.connect("add", lambda x: x.annotation.set_text(df.columns.tolist()[x.target.index]))
IndexError: list index out of range
我如何解决它？
