3

我正在使用树存储。封闭表模式。

https://towardsdatascience.com/closure-table-pattern-to-model-hierarchies-in-nosql-c1be6a87e05b

如何获得没有孙子和曾孙的子节点?

在此处输入图像描述

我有一个 sql 查询:

SELECT p.id, p.name, count(*) - l.level AS level 
FROM   tree_Path t, 
       ( SELECT count(*) -1 AS level 
         FROM tree_path 
         WHERE children = 3
       ) l, 
       (  SELECT * 
          FROM category_name f 
               INNER JOIN tree_Path t 
                    ON f.id = t.children 
           WHERE t.parent = 3 
           AND t.children!=t.parent
        ) p 
WHERE p.children = t.children 
GROUP BY p.id, p.name, l.level;

它返回一棵完整的后代树,包括孙子和曾孙。

    +----+----------------------------+-------+
    | id | name                       | level |
    +----+----------------------------+-------+
    |  7 | Audio & Video Accessories  |     2 |
    |  8 | Camera & Photo Accessories |     2 |
    | 15 | 3D Glasses                 |     3 |
    | 16 | Antennas                   |     3 |
    | 17 | Accessory Bundles          |     3 |
    | 18 | Bags & Cases               |     3 |
    +----+----------------------------+-------+

我需要归还没有孙子和曾孙的孩子。

    +----+----------------------------+-------+
    | id | name                       | level |
    +----+----------------------------+-------+
    |  7 | Audio & Video Accessories  |     2 |
    |  8 | Camera & Photo Accessories |     2 |
    +----+----------------------------+-------+

怎么做?

数据库测试

-- phpMyAdmin SQL Dump
-- version 5.1.0
-- https://www.phpmyadmin.net/
--
-- Host: localhost
-- Generation Time: Aug 02, 2021 at 01:15 PM
-- Server version: 8.0.25
-- PHP Version: 8.0.3

SET SQL_MODE = "NO_AUTO_VALUE_ON_ZERO";
START TRANSACTION;
SET time_zone = "+00:00";


/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;
/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;
/*!40101 SET NAMES utf8mb4 */;

--
-- Database: `closure_table`
--

-- --------------------------------------------------------

--
-- Table structure for table `category_name`
--

CREATE TABLE `category_name` (
  `id` bigint NOT NULL,
  `name` varchar(255) COLLATE utf8mb4_ru_0900_ai_ci DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_ru_0900_ai_ci;

--
-- Dumping data for table `category_name`
--

INSERT INTO `category_name` (`id`, `name`) VALUES
(1, 'Electronics'),
(2, 'Computers'),
(3, 'Accessories & Supplies'),
(4, 'Camera & Photo'),
(5, 'Computer accessories and peripherals'),
(6, 'Computer components'),
(7, 'Audio & Video Accessories'),
(8, 'Camera & Photo Accessories'),
(9, 'Accessories'),
(10, 'Bags & Cases'),
(11, 'Audio & Video Accessories'),
(12, 'Blank Media'),
(13, 'Computer screws'),
(14, 'Table Barebones'),
(15, '3D Glasses'),
(16, 'Antennas'),
(17, 'Accessory Bundles'),
(18, 'Bags & Cases'),
(19, 'Accessory Kits'),
(20, 'Bags & Cases'),
(21, 'Bag & Case Accessories'),
(22, 'Binocular Cases'),
(23, 'Computer headsets'),
(24, 'Computer microphones'),
(25, 'Discs BD-R'),
(26, 'Discs BD-RE'),
(27, 'bolts'),
(28, 'frame'),
(29, 'lamps'),
(30, 'coasters');

-- --------------------------------------------------------

--
-- Table structure for table `tree_path`
--

CREATE TABLE `tree_path` (
  `children` bigint NOT NULL,
  `parent` bigint NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_ru_0900_ai_ci;

--
-- Dumping data for table `tree_path`
--

INSERT INTO `tree_path` (`children`, `parent`) VALUES
(1, 1),
(3, 1),
(4, 1),
(7, 1),
(8, 1),
(9, 1),
(10, 1),
(15, 1),
(16, 1),
(17, 1),
(18, 1),
(19, 1),
(20, 1),
(21, 1),
(22, 1),
(2, 2),
(5, 2),
(6, 2),
(11, 2),
(12, 2),
(13, 2),
(14, 2),
(23, 2),
(24, 2),
(25, 2),
(26, 2),
(27, 2),
(28, 2),
(29, 2),
(30, 2),
(3, 3),
(7, 3),
(8, 3),
(15, 3),
(16, 3),
(17, 3),
(18, 3),
(4, 4),
(9, 4),
(10, 4),
(19, 4),
(20, 4),
(21, 4),
(22, 4),
(5, 5),
(11, 5),
(12, 5),
(23, 5),
(24, 5),
(25, 5),
(26, 5),
(6, 6),
(13, 6),
(14, 6),
(27, 6),
(28, 6),
(29, 6),
(30, 6),
(7, 7),
(15, 7),
(16, 7),
(8, 8),
(17, 8),
(18, 8),
(9, 9),
(19, 9),
(20, 9),
(10, 10),
(21, 10),
(22, 10),
(11, 11),
(23, 11),
(24, 11),
(12, 12),
(25, 12),
(26, 12),
(13, 13),
(27, 13),
(28, 13),
(14, 14),
(29, 14),
(30, 14),
(15, 15),
(16, 16),
(17, 17),
(18, 18),
(19, 19),
(20, 20),
(21, 21),
(22, 22),
(23, 23),
(24, 24),
(25, 25),
(26, 26),
(27, 27),
(28, 28),
(29, 29),
(30, 30);

--
-- Indexes for dumped tables
--

--
-- Indexes for table `category_name`
--
ALTER TABLE `category_name`
  ADD PRIMARY KEY (`id`);

--
-- Indexes for table `tree_path`
--
ALTER TABLE `tree_path`
  ADD PRIMARY KEY (`children`,`parent`),
  ADD KEY `FK_PARENT` (`parent`);

--
-- AUTO_INCREMENT for dumped tables
--

--
-- AUTO_INCREMENT for table `category_name`
--
ALTER TABLE `category_name`
  MODIFY `id` bigint NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=31;

--
-- Constraints for dumped tables
--

--
-- Constraints for table `tree_path`
--
ALTER TABLE `tree_path`
  ADD CONSTRAINT `FK_CHILDREN` FOREIGN KEY (`children`) REFERENCES `category_name` (`id`) ON DELETE CASCADE,
  ADD CONSTRAINT `FK_PARENT` FOREIGN KEY (`parent`) REFERENCES `category_name` (`id`) ON DELETE CASCADE;
COMMIT;

/*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;
/*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */;
/*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;
4

1 回答 1

2

假设您想要 level = 2 结果并且没有更大的后代,请使用HAVING子句:

SELECT p.id, p.name, count(*) - l.level AS levelx
FROM   tree_path t, 
       ( SELECT count(*) -1 AS level 
         FROM tree_path 
         WHERE children = 3
       ) l, 
       (  SELECT * 
          FROM category_name f 
               INNER JOIN tree_path t 
                    ON f.id = t.children 
           WHERE t.parent = 3 
           AND t.children!=t.parent
        ) p 
WHERE p.children = t.children 
GROUP BY p.id, p.name, l.level
HAVING levelx = 2
;

在小提琴中查看您的 SQL:

使用 HAVING 子句调整 SQL 的工作测试用例

于 2021-08-04T13:01:33.317 回答