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呃……我保证我在网上彻底搜索过这个问题,但找不到令人满意的答案,所以>.<

我正在尝试为我的 python 应用程序创建一个“控制器”,我的意思是,它应该被执行然后生成服务器,等待获取退出信号,如果需要,重新启动脚本。

这段代码非常混乱,但这就是我到目前为止所提供的......它总是以无法识别的 exitSignal 1 返回,甚至不会产生服务器进程!有人可以给我一盏灯吗?

#Server controller version 0.1
import os
import time
from datetime import datetime

Log = file("C:/Users/Admin/Desktop/Python/Server/WIP.log", 'w')

def runServer():
    exitSignal = os.spawnv(os.P_WAIT, 'C:/Python2.7/python.exe', ['python.exe',         'C:/Users/Admin/Desktop/Python/Server/WIP.py'])
    print str(datetime.today())+" - Server started"
    Log.write("\n"+str(datetime.today())+" - Server started")

    if exitSignal == "0":
        print str(datetime.today())+" - Server exited succesfully."
        Log.write("\n"+str(datetime.today())+" - Server exited succesfully.")

    elif exitSignal == "10":
        print str(datetime.today())+" - Rebooting server immediately."
        Log.write("\n"+str(datetime.today())+" - Rebooting server immediately.")
        runServer()

    elif exitSignal == "11":
        print str(datetime.today())+" - Rebooting server in 5 minutes."
        Log.write("\n"+str(datetime.today())+" - Rebooting server in 5 minutes.")
        time.sleep(300)
        runServer()
        print str(datetime.today())+" - Server rebooted."
        Log.write("\n"+str(datetime.today())+" - Server rebooted.")

    else:
        print str(datetime.today())+" - Unrecognized exitSignal code: %s" % str(exitSignal)
        Log.write("\n"+str(datetime.today())+" - Unrecognized exitSignal code: %s" % str(exitSignal))

if __name__ == "__main__":
    print str(datetime.today())+" - Controller started."
    Log.write("\n"+str(datetime.today())+" - Controller started")
    runServer()

抱歉代码乱七八糟!(=^,^=)

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1 回答 1

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如此处所述, os.spawnv 是一个已弃用的方法,您应该使用 subprocess模块

除此之外,如果您总是返回 1 并且没有生成进程,则可能是由于服务器代码的路径错误或服务器部分的代码错误。如果您手动启动服务器会发生什么?

于 2011-07-28T18:34:42.727 回答