codeigniter - CodeIgniter 3 代码不会将数据库中的数据添加到 2 个不同的表中（user_info 和 phone_info）

Question

问题是当我输入一个新名称时，没有添加任何数据。当我输入一个已经存在的名称时，也会发生类似的事情。尽管如此，没有数据被添加到数据库中。我还是 CodeIgniter 的新手，并且不完全确定我在模型中的查询构建器是否正确。

在模型中，我检查名称是否已经存在，仅将数据插入phone_info表中。IF 名称不存在我将数据插入到user_infoandphone_info中。

控制器：

public function addData()
{
    $name = $this->input->post('name');
    $contact_num = $this->input->post('contact_num');
    if($name == '') {
        $result['message'] = "Please enter contact name";
    } elseif($contact_num == '') {
        $result['message'] = "Please enter contact number";
    } else {
        $result['message'] = "";
        $data = array(
            'name' => $name,
            'contact_num' => $contact_num
        );
        $this->m->addData($data);
    }
    echo json_encode($result);
}

模型：

public function addData($data)
{
    if(mysqli_num_rows($data['name']) > 0) {
        $user = $this->db->get_where('user_info', array('name' => $data['name']))->result_array();
        $user_id = $user['id'];
        $phone_info = array(
            'contact_num' => $data['contact_num'],
            'user_id' => $user_id
        );
        $this->db->insert('phone_info',$phone_info);
    } else {
        $user_info = array(
            'name' => $data['name']
        );
        $this->db->insert('user_info', $user_info);
        $user = $this->db->get_where('user_info', array('name' => $data['name']))->result_array();
        $user_id = $user['id'];
        $phone_info = array(
            'contact_num' => $data['contact_num'],
            'user_id' => $user_id
        );
        $this->db->insert('phone_info', $phone_info);
    }
}

数据库表用户信息：

数据库表电话信息：

Answer 1

Extend and change your model to this:

public function findByTitle($name)
{
    $this->db->where('name', $name);
    return $this->result();
}

public function addData($data)
{
    if(count($this->findByTitle($data['name'])) > 0) {
        //.. your code
    } else {
        //.. your code
    }
}

---

Explanation:

This:

if(mysqli_num_rows($data['name']) > 0)

..is not working to find database entries by name. To do this you can use codeigniters built in model functions and benefit from the MVC Pattern features, that CodeIgniter comes with.

I wrapped the actual findByName in a function so you can adapt this to other logic and use it elswehere later on. This function uses the query() method.

Read more about CodeIgniters Model Queries in the documentation.

---

Sidenote: mysqli_num_rows is used to iterate find results recieved by mysqli_query. This is very basic sql querying and you do not need that in a MVC-Framework like CodeIgniter. If you every appear to need write a manual sql-query, even then you should use CodeIgniters RawQuery methods.