0

我的表如下所示:

ID 时间
1 2021-07-17 17:44:26
2 2021-07-17 17:44:26
3 2021-07-17 17:44:26
4 2021-07-17 17:44:31
5 2021-07-17 17:44:31
6 2021-07-17 17:44:31
7 2021-07-17 17:44:36
8 2021-07-17 17:44:36
9 2021-07-17 17:44:36
10 2021-07-17 17:44:41
11 2021-07-17 17:44:41
12 2021-07-17 17:44:41
13 2021-07-17 17:44:51
14 2021-07-17 17:44:51
15 2021-07-17 17:44:51
16 2021-07-17 17:44:56
17 2021-07-17 17:44:56
18 2021-07-17 17:44:56
19 2021-07-17 17:45:02
20 2021-07-17 17:45:02
21 2021-07-17 17:45:02

我有 MySQL 8.0.21

总是接下来的 3 行有相同的时间,然后 beetwen 通常是 5 秒的时间间隔,如何找到所有超过 8 秒的间隔并计算间隔时间以获得类似的结果:

gap_id gap_time_start 间隙长度
1 2021-07-17 17:44:41 10
4

1 回答 1

0

如果您使用的是 MySQL 8+,则可以LEAD()像这样使用窗口函数:

select * from (
    SELECT id as gap_id, 
        `time` as gap_start_time, 
        timediff( lead(`time`) over W, `time`) as gap_length 
        from `myTable` window w as (order by `time` asc)
    ) T where T.gap_length > 5;

输出:

12, 2021-07-17 17:44:41, 00:00:10
18, 2021-07-17 17:44:56, 00:00:06

参考:铅()

于 2021-07-19T01:00:24.003 回答