python - 所以在我的python代码运行后，我输入输入，程序就停止了。不知道逻辑错误是什么

Question

我正在尝试为 CSV 文件创建一个简单的解析器。我正在尝试使用最简单的方法来查看解析器以查找值（行）。

import csv
"""
with open('C:/MAIL07072021180029.csv', 'r') as file:
     proxy = csv.reader(file)
     for row in proxy:
         print(row[0])

"""

identifyingnumber = input("What is the number? ")

with open('C:/MAIL07072021180029.csv', 'r') as file:
    data = csv.reader(file)
    for row in data:
        if row[1] == (identifyingnumber):
            print(row)

在我运行代码并输入代理号码（识别号码，我的 excel 中的数据）之后。程序刚刚停止？它不是打印行。

这是我的 csv 文件中的示例数据：

Card Identifying Sequence
1873356

如果该行打印成功，我通过取出标识号打印出第 0 行。

这是某种逻辑错误吗？我无法弄清楚这一点。

Answer 1

您的 csv 文件中可能没有识别号，在这种情况下，由于您的“if”语句，不会打印任何内容。您可以检查您是否找到了该号码，如果是，则中断（如果您不想检查其他行以获取该号码的另一个实例），如果没有，则打印您从未找到该号码。

with open('C:/MAIL07072021180029.csv', 'r') as file:
    data = csv.reader(file)
    found = False
    for row in data:
        if row[1] == (identifyingnumber):
            print(row)
            found = True
            break    # if you don't want to look for more instances of identifyingnumber
    if not found:   # aka found == False
        print('I did not find any row[1] equal to', identifyingnumber)    

我强烈建议您尝试使用 Pandas。在 Pandas 中打开 csv，然后一次检查所有行的值，而不是遍历行。 https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.read_csv.html

import pandas as pd
df = pd.read_csv('C:/MAIL07072021180029.csv')
col1 = df.columns[1]
dfi = df[df[col1] == identifyingnumber]
dfi = dfi.reset_index()
print(dfi['index'].tolist())        # there could be more than 1 row with the identifier

编辑以将我们在评论中讨论的所有内容放在一起：

file_list = ['C:/MAIL07072021180029.csv','C:/other_file.csv']
for f in file_list:
    with open(f, 'r') as file:
        data = csv.reader(file)
        found = False
        for row in data:
            if found:   # aka found == True - if any column found the value, break to stop iterating
                break
            for col in range(1, len(row)):   # start at 1 to skip col 0
                if row[col] == identifyingnumber:  # (identifyingnumber) is a tuple(), you probably don't want that
                    print(row)
                    found = True
                    break    # if you don't want to look for more instances of identifyingnumber
        if not found:   # aka found == False
            print('I did not find any row[1] equal to', identifyingnumber)