我真的需要以下建议,尝试使用数据库函数 getpreviousorders..
SELECT o1.* FROM "sample"."order" o1 JOIN "sample".patient p1 ON o1.patient_id = p1.id
WHERE o1.sample_id != _sampleId AND p1.mrn = _mrn
AND ((o1.collection_date is not null AND o1.collection_date >= _createdDate)
OR (o1.collection_date is null AND o1.receipt_date is not null
AND o1.receipt_date >= _createdDate))
UNION
(SELECT o2.* FROM "sample"."order" o2 JOIN "sample".patient p2 ON o2.patient_id = p2.id
WHERE (o2.status = 1 or o2.status = 2 OR o2.status = 3) AND o2.sample_id != _sampleId
AND p2.mrn = _mrn
AND ((o2.collection_date is not null AND o2.collection_date < _createdDate)
OR (o2.collection_date is null AND o2.receipt_date is not null
AND o2.receipt_date < _createdDate)) ORDER by created_date DESC LIMIT 1)
ORDER by collection_date DESC, receipt_date DESC, created_date DESC;
获得 199 个先前订单的总时间为 2628 毫秒,而 findPreviousOrders 函数花费的所有时间最多:2535 毫秒
分析查询和代码片段!!!


