这是我的简化代码。我需要更改函数中的 pdp_state。但状态仍然是'a'。我不明白为什么克隆 Rc 不起作用。我还检查了这个克隆的结构,它工作正常。
#[derive(Clone,Copy)]
enum PDPStatus{
a,
b
}
struct network{
pdp_state:Rc<RefCell<PDPStatus>>,
}
impl network{
fn set(&mut self){
let mut t = *self.pdp_state.clone().borrow_mut();
match t {
a => {let m1 = self.pdp_state.clone();
let mut a = (*m1).borrow_mut() ;
*a = PDPStatus::b;
println!("a");},
b=> {let m1 = self.pdp_state.clone();m1.replace( PDPStatus::a);
println!("b");},
};
}
}
fn main() {
let mut network1 = network::new();
network1.set();
network1.set();
network1.set();
network1.set();
}
更新:我的 set 函数看起来像这样。我需要两个可以访问 pdp_state 的闭包。我将这些闭包作为回调传递。我确信这些关闭不会一起调用。
fn set(&mut self){
let borrowed_pdp_status = self.pdp_state.borrow().clone();
match borrowed_pdp_status {
PDPStatus::a => {
let mut state = self.pdp_state.clone();
let mut closuree = || state = Rc::new(RefCell::new(PDPStatus::b));
let mut state1 = self.pdp_state.clone();
let mut closuree1 = || state1 = Rc::new(RefCell::new(PDPStatus::b));
closuree();
closuree1();
println!("a");
},
PDPStatus::b => {
let mut closuree = || self.pdp_state = Rc::new(RefCell::new(PDPStatus::a));
closuree();
println!("b");
},
};
}