152

一个程序,它创建多个在可连接队列上工作的进程Q,并且最终可能会操纵全局字典D来存储结果。(因此每个子进程都可以D用来存储其结果并查看其他子进程产生的结果)

如果我在子进程中打印字典 D,我会看到对其进行的修改(即在 D 上)。但是在主进程加入Q之后,如果我打印D,它就是一个空字典!

我知道这是一个同步/锁定问题。有人可以告诉我这里发生了什么,以及如何同步对 D 的访问吗?

4

5 回答 5

211

一般答案涉及使用Manager对象。改编自文档:

from multiprocessing import Process, Manager

def f(d):
    d[1] += '1'
    d['2'] += 2

if __name__ == '__main__':
    manager = Manager()

    d = manager.dict()
    d[1] = '1'
    d['2'] = 2

    p1 = Process(target=f, args=(d,))
    p2 = Process(target=f, args=(d,))
    p1.start()
    p2.start()
    p1.join()
    p2.join()

    print d

输出:

$ python mul.py 
{1: '111', '2': 6}
于 2011-07-26T15:38:50.523 回答
33

多处理不像线程。每个子进程都会得到一份主进程内存的副本。通常状态是通过通信(管道/套接字)、信号或共享内存共享的。

多处理为您的用例提供了一些抽象 - 通过使用代理或共享内存将共享状态视为本地:http: //docs.python.org/library/multiprocessing.html#sharing-state-between-processes

相关部分:

于 2011-07-26T15:38:29.280 回答
28

除了@senderle 在这里,有些人可能还想知道如何使用multiprocessing.Pool.

好消息是该实例有一个.Pool()方法可以manager模仿所有熟悉的顶级 API multiprocessing

from itertools import repeat
import multiprocessing as mp
import os
import pprint

def f(d: dict) -> None:
    pid = os.getpid()
    d[pid] = "Hi, I was written by process %d" % pid

if __name__ == '__main__':
    with mp.Manager() as manager:
        d = manager.dict()
        with manager.Pool() as pool:
            pool.map(f, repeat(d, 10))
        # `d` is a DictProxy object that can be converted to dict
        pprint.pprint(dict(d))

输出:

$ python3 mul.py 
{22562: 'Hi, I was written by process 22562',
 22563: 'Hi, I was written by process 22563',
 22564: 'Hi, I was written by process 22564',
 22565: 'Hi, I was written by process 22565',
 22566: 'Hi, I was written by process 22566',
 22567: 'Hi, I was written by process 22567',
 22568: 'Hi, I was written by process 22568',
 22569: 'Hi, I was written by process 22569',
 22570: 'Hi, I was written by process 22570',
 22571: 'Hi, I was written by process 22571'}

这是一个稍微不同的示例,其中每个进程只是将其进程 ID 记录到全局DictProxy对象d中。

于 2019-04-23T16:58:39.687 回答
20

我想分享我自己的工作,它比 Manager 的 dict 更快,并且比使用大量内存且不适用于 Mac OS 的 pyshmht 库更简单、更稳定。虽然我的 dict 只适用于纯字符串并且目前是不可变的。我使用线性探测实现并将键和值对存储在表之后的单独内存块中。

from mmap import mmap
import struct
from timeit import default_timer
from multiprocessing import Manager
from pyshmht import HashTable


class shared_immutable_dict:
    def __init__(self, a):
        self.hs = 1 << (len(a) * 3).bit_length()
        kvp = self.hs * 4
        ht = [0xffffffff] * self.hs
        kvl = []
        for k, v in a.iteritems():
            h = self.hash(k)
            while ht[h] != 0xffffffff:
                h = (h + 1) & (self.hs - 1)
            ht[h] = kvp
            kvp += self.kvlen(k) + self.kvlen(v)
            kvl.append(k)
            kvl.append(v)

        self.m = mmap(-1, kvp)
        for p in ht:
            self.m.write(uint_format.pack(p))
        for x in kvl:
            if len(x) <= 0x7f:
                self.m.write_byte(chr(len(x)))
            else:
                self.m.write(uint_format.pack(0x80000000 + len(x)))
            self.m.write(x)

    def hash(self, k):
        h = hash(k)
        h = (h + (h >> 3) + (h >> 13) + (h >> 23)) * 1749375391 & (self.hs - 1)
        return h

    def get(self, k, d=None):
        h = self.hash(k)
        while True:
            x = uint_format.unpack(self.m[h * 4:h * 4 + 4])[0]
            if x == 0xffffffff:
                return d
            self.m.seek(x)
            if k == self.read_kv():
                return self.read_kv()
            h = (h + 1) & (self.hs - 1)

    def read_kv(self):
        sz = ord(self.m.read_byte())
        if sz & 0x80:
            sz = uint_format.unpack(chr(sz) + self.m.read(3))[0] - 0x80000000
        return self.m.read(sz)

    def kvlen(self, k):
        return len(k) + (1 if len(k) <= 0x7f else 4)

    def __contains__(self, k):
        return self.get(k, None) is not None

    def close(self):
        self.m.close()

uint_format = struct.Struct('>I')


def uget(a, k, d=None):
    return to_unicode(a.get(to_str(k), d))


def uin(a, k):
    return to_str(k) in a


def to_unicode(s):
    return s.decode('utf-8') if isinstance(s, str) else s


def to_str(s):
    return s.encode('utf-8') if isinstance(s, unicode) else s


def mmap_test():
    n = 1000000
    d = shared_immutable_dict({str(i * 2): '1' for i in xrange(n)})
    start_time = default_timer()
    for i in xrange(n):
        if bool(d.get(str(i))) != (i % 2 == 0):
            raise Exception(i)
    print 'mmap speed: %d gets per sec' % (n / (default_timer() - start_time))


def manager_test():
    n = 100000
    d = Manager().dict({str(i * 2): '1' for i in xrange(n)})
    start_time = default_timer()
    for i in xrange(n):
        if bool(d.get(str(i))) != (i % 2 == 0):
            raise Exception(i)
    print 'manager speed: %d gets per sec' % (n / (default_timer() - start_time))


def shm_test():
    n = 1000000
    d = HashTable('tmp', n)
    d.update({str(i * 2): '1' for i in xrange(n)})
    start_time = default_timer()
    for i in xrange(n):
        if bool(d.get(str(i))) != (i % 2 == 0):
            raise Exception(i)
    print 'shm speed: %d gets per sec' % (n / (default_timer() - start_time))


if __name__ == '__main__':
    mmap_test()
    manager_test()
    shm_test()

在我的笔记本电脑上,性能结果是:

mmap speed: 247288 gets per sec
manager speed: 33792 gets per sec
shm speed: 691332 gets per sec

简单的使用示例:

ht = shared_immutable_dict({'a': '1', 'b': '2'})
print ht.get('a')
于 2016-08-18T14:07:01.070 回答
3

也许您可以尝试pyshmht,为 Python 共享基于内存的哈希表扩展。

注意

  1. 未经过全面测试,仅供参考。

  2. 它目前缺乏用于多处理的锁定/sem 机制。

于 2014-04-25T04:28:36.330 回答