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我尝试使用 oEmbed 将视频 url 转换为嵌入 url,但是:

在此处输入图像描述

当我print(video_url_api_data)不断返回<Response [404]>

我在 google 中使用 url 检查了它:https ://vimeo.com/api/oembed.json?url=https://vimeo.com/570924262

我在代码中做错了什么?我必须在状态部分添加什么?

此状态部分:

vimeo_authorization_url = v.auth_url(
                ['private'],
                'http://127.0.0.1:8000/',
                1 #status
            ) 

我将 1 随机放入,它可以工作。

import json, vimeo, requests
    
class article_upload(View):
     def post(self ,request, *args, **kwargs):    
            v = vimeo.VimeoClient(
                token='****',
                key='****',
                secret='****'
            )
            file_data = request.FILES["file_data"]
            path = file_data.temporary_file_path()
            try:
                vimeo_authorization_url = v.auth_url(
                    ['private'],
                    'http://127.0.0.1:8000/',
                    1 #status
                )
                video_uri = v.upload(path, data={'name': '비디오 제목', 'description': '설명'})
                video_data = v.get(video_uri + '?fields=link').json()
                video_url = video_data['link']
                params={"url": video_url}
                video_url_api_data = requests.get('https://vimeo.com/api/oembed.json', params=params)
                
                
                return render(request, 'account/myvideopage.html', {context(I made it)})
    
            except vimeo.exceptions.VideoUploadFailure as e:
                print("ohohohohohoh...vimeo error")
    
            finally:
                file_data.close()  # Theoretically this should remove the file
                if os.path.exists(path):
                    os.unlink(path)  # But this will do it, barring permissions
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1 回答 1

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我之前解决了!问题是……延迟时间!

在这里...我上传视频.. 其大小至少为 10MB

video_uri = v.upload(path, data={'name': '비디오 제목', 'descriptio...

在我完成上传之前,我使用 api 请求信息...

 video_url_api_data = requests.get('https://vimeo.com/api/oem...
于 2021-07-19T23:37:55.887 回答