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我已经从自定义维度（用户 ID 和商家）中留下了连接值。我还想添加交易。我可以就如何将其添加到此查询中获得一些建议吗？还是我必须完全改变结构？这就是我尝试的方式，但是我收到一个语法错误，说它需要 FROM 语句所在的结束输入。

merchants.merchant_Id,
otherMerchants.merchant_id AS otherMerchants,
merchants.market AS market,
COUNT (merchants.transactions) AS transactions,
COUNT(DISTINCT merchants.userId) users
FROM(

SELECT 
#här hämtar vi alla userIds och merchantIds
(SELECT VALUE FROM UNNEST(customDimensions) WHERE INDEX = 3) userid,
(SELECT VALUE FROM UNNEST(customDimensions) WHERE INDEX = 4) merchant_Id,
(SELECT VALUE FROM UNNEST (customDimensions) WHERE INDEX = 8) market,
hits.transaction.transactionId) as transactions

 FROM `qliro-66ee8.128389777.ga_sessions_20210628`
 UNNEST (hits) AS hits
) merchants

LEFT JOIN 

(
SELECT 
#här hämtar vi alla userIds och merchantIds igen för att kunna nyckla ihop det
(SELECT VALUE FROM UNNEST(customDimensions) WHERE INDEX = 3) userid,
(SELECT VALUE FROM UNNEST(customDimensions) WHERE INDEX = 4) merchant_id,
(SELECT VALUE FROM UNNEST (customDimensions) WHERE INDEX = 8) market,
hits.transaction.transactionId) as transactions

 FROM `qliro-66ee8.128389777.ga_sessions_20210628`
 UNNEST (hits) AS hits
) otherMerchants

#nycklar på att det är samma user samt inte samma merchant för att inte få dubbelräkning
#nycklar på att det är samma user samt inte samma merchant för att inte få dubbelräkning
ON merchants.userId = otherMerchants.userid
AND merchants.merchant_Id != otherMerchants.merchant_id
AND merchants.transactions = otherMerchants.transactions
AND merchants.market = otherMerchants.market

GROUP BY 1,2,3
4

1 回答 1

1

我觉得你很亲近！你应该做这样的事情

SELECT
merchants.merchant_Id,
otherMerchants.merchant_id AS otherMerchants,
merchants.market AS market,
SUM(merchants.transactions) AS transactions,
COUNT(DISTINCT merchants.userId) users
FROM(

SELECT 
(SELECT VALUE FROM UNNEST(t1.customDimensions) WHERE INDEX = 3) userid,
(SELECT VALUE FROM UNNEST(t1.customDimensions) WHERE INDEX = 4) merchant_Id,
(SELECT VALUE FROM UNNEST (t1.customDimensions) WHERE INDEX = 8) market,
count(distinct hits.transaction.transactionId) as transactions

 FROM `qliro-66ee8.128389777.ga_sessions_20210628` t1,
 UNNEST (hits) AS hits
 GROUP BY 1,2,3
) merchants

LEFT JOIN 

(
SELECT 
#här hämtar vi alla userIds och merchantIds igen för att kunna nyckla ihop det
(SELECT VALUE FROM UNNEST(customDimensions) WHERE INDEX = 3) userid,
(SELECT VALUE FROM UNNEST(customDimensions) WHERE INDEX = 4) merchant_id,
(SELECT VALUE FROM UNNEST (customDimensions) WHERE INDEX = 8) market

 FROM `qliro-66ee8.128389777.ga_sessions_20210628`
) otherMerchants

ON merchants.userId = otherMerchants.userid
AND merchants.merchant_Id != otherMerchants.merchant_id
AND merchants.market = otherMerchants.market

GROUP BY 1,2,3

编辑：查询中缺少 GROUP BY 语句

于 2021-07-02T14:15:09.843 回答