4

我有两个这样的表：

Table1ID               Table2ID    Table1ID  SomeDate
--------               ------------------------------
1                      1           1         2011-01-01
2                      2           1         2011-01-02
3                      3           2         2011-01-01
4                      4           3         2011-01-01
                       5           3         2011-01-02
                       6           3         2011-01-03
                       7           4         2011-01-01
                       8           4         2011-01-02

我需要将值插入到第三个表中，该表给我来自 Table2 的两个值，以及在 Table1ID 上分组的“序列”值。我试过这个，但我总是得到 1 的序列值。

;WITH Sequences AS (
    SELECT t1.Table1ID,
           MAX(ISNULL(t3.Sequence, 0)) AS [MaxSequence]
    FROM Table1 t1
    LEFT JOIN Table3 t3 (NOLOCK) ON t1.Table1ID = t3.Table1ID
    GROUP BY t1.Table1ID
)
INSERT INTO Table3 ( Table1ID, Table2ID, Sequence )
SELECT t1.Table1ID,
       t2.Table2ID,
       s.MaxSequence + 1
FROM Table1 t1 (NOLOCK)
JOIN Table2 t2 (NOLOCK) ON t1.Table1ID = t2.Table2ID
JOIN Sequences s ON t2.Table1ID = s.Table1ID
ORDER BY t2.SomeDate

我想要的是这样的结果集：

Table2ID    Table1ID  Sequence
------------------------------
1           1         1
2           1         2
3           2         1
4           3         1
5           3         2
6           3         3
7           4         1
8           4         2

我知道我可能在这里遗漏了一些愚蠢简单的东西，但我被困住了。

4

1 回答 1

4 
insert into Table3 (Table2ID, Table1ID, Sequence)
select
  Table2ID,
  Table1ID,
  row_number() over(partition by Table1ID order by Table2ID)
from Table2

要测试的东西：

declare @Table2 table
(
  Table2ID int identity,
  Table1ID int
)
insert into @Table2 values
(1),(1),
(2),
(3),(3),(3),
(4),(4)

declare @Table3 table
(
  Table2ID int, 
  Table1ID int, 
  Sequence int
)

insert into @Table3 (Table2ID, Table1ID, Sequence)
select
  Table2ID,
  Table1ID,
  row_number() over(partition by Table1ID order by Table2ID)
from @Table2

select *
from @Table3

结果：

Table2ID    Table1ID    Sequence
----------- ----------- -----------
1           1           1
2           1           2
3           2           1
4           3           1
5           3           2
6           3           3
7           4           1
8           4           2
于 2011-07-25T17:27:24.840 回答