26

需要将一些文件动态打包成 .zip 以创建 SCORM 包，有人知道如何使用代码来完成吗？是否也可以在 .zip 中动态构建文件夹结构？

4

9 回答 9

22

DotNetZip很适合这个。

您可以将 zip 直接写入 Response.OutputStream。代码如下所示：

    Response.Clear();
    Response.BufferOutput = false; // for large files...
    System.Web.HttpContext c= System.Web.HttpContext.Current;
    String ReadmeText= "Hello!\n\nThis is a README..." + DateTime.Now.ToString("G"); 
    string archiveName= String.Format("archive-{0}.zip", 
                                      DateTime.Now.ToString("yyyy-MMM-dd-HHmmss")); 
    Response.ContentType = "application/zip";
    Response.AddHeader("content-disposition", "filename=" + archiveName);

    using (ZipFile zip = new ZipFile())
    {
        // filesToInclude is an IEnumerable<String>, like String[] or List<String>
        zip.AddFiles(filesToInclude, "files");            

        // Add a file from a string
        zip.AddEntry("Readme.txt", "", ReadmeText);
        zip.Save(Response.OutputStream);
    }
    // Response.End();  // no! See http://stackoverflow.com/questions/1087777
    Response.Close();

DotNetZip 是免费的。

于 2009-03-26T06:24:54.090 回答
17

您不必再使用外部库了。System.IO.Packaging 具有可用于将内容放入 zip 文件的类。然而，它并不简单。 这是一个带有示例的博客文章（它在最后；挖掘它）。

该链接不稳定，因此这是 Jon 在帖子中提供的示例。

using System;
using System.IO;
using System.IO.Packaging;

namespace ZipSample
{
    class Program
    {
        static void Main(string[] args)
        {
            AddFileToZip("Output.zip", @"C:\Windows\Notepad.exe");
            AddFileToZip("Output.zip", @"C:\Windows\System32\Calc.exe");
        }

        private const long BUFFER_SIZE = 4096;

        private static void AddFileToZip(string zipFilename, string fileToAdd)
        {
            using (Package zip = System.IO.Packaging.Package.Open(zipFilename, FileMode.OpenOrCreate))
            {
                string destFilename = ".\\" + Path.GetFileName(fileToAdd);
                Uri uri = PackUriHelper.CreatePartUri(new Uri(destFilename, UriKind.Relative));
                if (zip.PartExists(uri))
                {
                    zip.DeletePart(uri);
                }
                PackagePart part = zip.CreatePart(uri, "",CompressionOption.Normal);
                using (FileStream fileStream = new FileStream(fileToAdd, FileMode.Open, FileAccess.Read))
                {
                    using (Stream dest = part.GetStream())
                    {
                        CopyStream(fileStream, dest);
                    }
                }
            }
        }

        private static void CopyStream(System.IO.FileStream inputStream, System.IO.Stream outputStream)
        {
            long bufferSize = inputStream.Length < BUFFER_SIZE ? inputStream.Length : BUFFER_SIZE;
            byte[] buffer = new byte[bufferSize];
            int bytesRead = 0;
            long bytesWritten = 0;
            while ((bytesRead = inputStream.Read(buffer, 0, buffer.Length)) != 0)
            {
                outputStream.Write(buffer, 0, bytesRead);
                bytesWritten += bytesRead;
            }
        }
    }
}
于 2009-03-25T14:52:20.510 回答
7

你可以看看SharpZipLib。这是一个示例。

于 2009-03-25T14:32:26.267 回答
7

如果您使用的是 .NET Framework 4.5 或更高版本，则可以避免使用第三方库并使用本System.IO.Compression.ZipArchive机类。

这是一个使用 MemoryStream 和几个字节数组表示两个文件的快速代码示例：

byte[] file1 = GetFile1ByteArray();
byte[] file2 = GetFile2ByteArray();

using (MemoryStream ms = new MemoryStream())
{
    using (var archive = new ZipArchive(ms, ZipArchiveMode.Create, true))
    {
        var zipArchiveEntry = archive.CreateEntry("file1.txt", CompressionLevel.Fastest);
        using (var zipStream = zipArchiveEntry.Open()) zipStream.Write(file1, 0, file1.Length);
        zipArchiveEntry = archive.CreateEntry("file2.txt", CompressionLevel.Fastest);
        using (var zipStream = zipArchiveEntry.Open()) zipStream.Write(file2, 0, file2.Length);
    }
    return File(ms.ToArray(), "application/zip", "Archive.zip");
}

您可以在返回ActionResult: 的 MVC 控制器中使用它，或者，如果您需要以物理方式创建 zip 存档，您可以将其保存MemoryStream到磁盘或将其完全替换为FileStream.

有关此主题的更多信息，您还可以阅读我博客上的这篇文章。

于 2017-05-17T19:07:41.490 回答
3

DotNetZip 非常易于使用... 在 ASP.Net 中创建 Zip 文件

于 2011-02-25T16:51:23.257 回答
1

为此，我使用了 chilkat 的免费组件：http: //www.chilkatsoft.com/zip-dotnet.asp。几乎完成了我需要的一切，但是我不确定动态构建文件结构。

于 2009-03-25T14:34:01.863 回答
1

能够使用 DotNetZip 做到这一点。您可以从 Visual Studio Nuget 包管理器或直接通过DotnetZip下载它。然后尝试下面的代码，

     /// <summary>
    /// Generate zip file and save it into given location
    /// </summary>
    /// <param name="directoryPath"></param>
    public void CreateZipFile(string directoryPath )
    {
        //Select Files from given directory
        List<string> directoryFileNames = Directory.GetFiles(directoryPath).ToList();
        using (ZipFile zip = new ZipFile())
        {
            zip.AddFiles(directoryFileNames, "");
            //Generate zip file folder into loation
            zip.Save("C:\\Logs\\ReportsMyZipFile.zip");
        }
    }

如果要将文件下载到客户端，请使用以下代码。

/// <summary>
    /// Generate zip file and download into client
    /// </summary>
    /// <param name="directoryPath"></param>
    /// <param name="respnse"></param>
    public void CreateZipFile(HttpResponse respnse,string directoryPath )
    {
        //Select Files from given directory
        List<string> directoryFileNames = Directory.GetFiles(directoryPath).ToList();
        respnse.Clear();
        respnse.BufferOutput = false;
        respnse.ContentType = "application/zip";
        respnse.AddHeader("content-disposition", "attachment; filename=MyFiles.zip");

        using (ZipFile zip = new ZipFile())
        {
            zip.CompressionLevel = CompressionLevel.None;
            zip.AddFiles(directoryFileNames, "");
            zip.Save(respnse.OutputStream);
        }

        respnse.flush();
    }
于 2018-04-12T15:21:45.377 回答
0

使用我们的Rebex ZIP组件“即时”创建 ZIP 文件。

以下示例对其进行了完整描述，包括创建子文件夹：

// prepare MemoryStream to create ZIP archive within
using (MemoryStream ms = new MemoryStream())
{
    // create new ZIP archive within prepared MemoryStream
    using (ZipArchive zip = new ZipArchive(ms))
    {            
         // add some files to ZIP archive
         zip.Add(@"c:\temp\testfile.txt");
         zip.Add(@"c:\temp\innerfile.txt", @"\subfolder");

         // clear response stream and set the response header and content type
         Response.Clear();
         Response.ContentType = "application/zip";
         Response.AddHeader("content-disposition", "filename=sample.zip");

         // write content of the MemoryStream (created ZIP archive) to the response stream
         ms.WriteTo(Response.OutputStream);
    }
}

// close the current HTTP response and stop executing this page
HttpContext.Current.ApplicationInstance.CompleteRequest();
于 2010-09-16T13:52:36.343 回答
0 
#region Create zip file in asp.net c#
        string DocPath1 = null;/*This varialble is Used for Craetting  the File path .*/
        DocPath1 = Server.MapPath("~/MYPDF/") + ddlCode.SelectedValue + "/" + txtYear.Value + "/" + ddlMonth.SelectedValue + "/";
        string[] Filenames1 = Directory.GetFiles(DocPath1);
        using (ZipFile zip = new ZipFile())
        {
            zip.AddFiles(Filenames, "Pdf");//Zip file inside filename
            Response.Clear();
            Response.BufferOutput = false;
            string zipName = String.Format("Zip_{0}.zip", DateTime.Now.ToString("yyyy-MMM-dd-HHmmss"));
            Response.ContentType = "application/zip";
            Response.AddHeader("content-disposition", "attachment; filename=" + zipName);
            zip.Save(Response.OutputStream);
            Response.End();
        }
        #endregion
于 2020-08-20T06:09:23.110 回答