flutter - 如何在flutter中实现通用链接？

Question

我处理深度链接并根据文档进行集成，但是当使用应用程序或浏览器打开添加 url 对话框时，这是我的功能，universal_link 的这两个函数，我在 mainfest 文件中添加了集成主机和方案：-

    Future<void> initDynamicLinks() async {
    FirebaseDynamicLinks.instance.onLink(
        onSuccess: (PendingDynamicLinkData dynamicLink) async {
      final Uri deepLink = dynamicLink?.link;

      if (deepLink != null) {
        // ignore: unawaited_futures
        Navigator.pushNamed(context, deepLink.path);
      }
            _createDynamicLink(false);

    }, onError: (OnLinkErrorException e) async {
      print('onLinkError');
      print(e.message);
    });

    final PendingDynamicLinkData data =
        await FirebaseDynamicLinks.instance.getInitialLink();
    final Uri deepLink = data?.link;

    if (deepLink != null) {
      // ignore: unawaited_futures
      Navigator.pushNamed(context, deepLink.path);
    }
  }

  Future<void> _createDynamicLink(bool short) async {
    setState(() {
      _isCreatingLink = true;
    });

    final DynamicLinkParameters parameters = DynamicLinkParameters(
      uriPrefix: 'https://emtahnatapp.page.link',
      link: Uri.parse('https://emtahnatapp.page.link/iho8'),
      androidParameters: AndroidParameters(
        packageName: 'com.emtahnatapp.eg',
        minimumVersion: 100,
      ),
     
      // iosParameters: IosParameters(
      //   bundleId: 'com.google.FirebaseCppDynamicLinksTestApp.dev',
      //   minimumVersion: '0',
      // ),
    );

    Uri url;
    if (short) {
      final ShortDynamicLink shortLink = await parameters.buildShortLink();
      url = shortLink.shortUrl;
    } else {
      url = await parameters.buildUrl();
    }

    setState(() {
      _linkMessage = url.toString();
      _isCreatingLink = false;
    });
  }
}