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在此处输入图像描述我在 phpmyadmin 中创建了这些表

付款表

DROP TABLE IF EXISTS Payment; 
CREATE TABLE IF NOT EXISTS Payment (
pay_id int(5) NOT NULL, 
number int(25) default NULL, 
amount decimal(20,2) default NULL,
CONSTRAINT Payment_pk_payid 
PRIMARY KEY (pay_id) ) 
ENGINE=InnoDB DEFAULT CHARSET=utf8;

Policy_payment 表

DROP TABLE IF EXISTS Policy_payment;
CREATE TABLE IF NOT EXISTS Policy_payment( 
id int(5) NOT NULL, 
policy_id int(5) NOT NULL, 
pay_id int(5) NOT NULL, 
date date default NULL, 
CONSTRAINT Policy_payment_pk_id_policyid_payid 
    PRIMARY KEY (id,policy_id,pay_id),
CONSTRAINT Policy_payment_fk_policyid 
    FOREIGN KEY (policy_id)
    REFERENCES Policy (policy_id), 
CONSTRAINT Policy_payment_fk_payid
    FOREIGN KEY (pay_id) 
    REFERENCES Payment (pay_id) ) 
ENGINE=InnoDB DEFAULT CHARSET=utf8;

因此，当我尝试在 Policy_payment 表中插入值时，会出现 #1452 错误。我究竟做错了什么？

-- 转储表 Policy_payment 的数据

INSERT INTO Policy_payment (
id, policy_id, pay_id, date) 
VALUES
('70111', '88881', '20001', '2019-01-10'), 
('70112', '88882', '20002', '2019-09-25'), 
('70113', '88883', '20003', '2019-04-18'), 
('70114', '88884', '20004', '2020-11-11'), 
('70115', '88885', '20005', '2020-06-23'), 
('70116', '88886', '20006', '2021-12-11'), 
('70117', '88887', '20007', '2021-08-20'), 
('70118', '88888', '20008', '2018-03-04'), 
('70119', '88889', '20009', '2018-03-20'), 
('70110', '88810', '20010', '2016-02-09');

在此处输入图像描述

这是错误 #1452 - 无法添加或更新子行：外键约束失败 ( S11185754. Policy_payment, CONSTRAINT Policy_payment_fk_payidFOREIGN KEY ( pay_id) REFERENCES Payment( pay_id))

谢谢

4

1 回答 1

0

You are trying to insert a record with a pay_id that doesn't match any record in the payment table i.e. exactly what the error message says.

于 2021-06-19T21:52:10.287 回答