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我为 Date 列中的缺失值而苦苦挣扎。在我的预处理管道 ( recipe-object) 中，我使用该step_impute_knn函数填充所有日期列中的缺失值。不幸的是，我收到以下错误：

分配的数据 pred_vals 必须与现有数据兼容。？列 avg_begin_first_contract .x 发生错误无法将双精度转换为日期

这是reprex一个版本，我在多个列中估算值，包括一Date列。Date如果我只将值估算到列中，这对我来说并不重要。结果是一样的。下面有一个reprex，它没有通过错误，因为没有Date使用列。

以前有人遇到过这个问题吗？

library(tidyverse)
library(tidymodels)

iris <- iris %>%
  mutate(Plucked = sample(seq(as.Date("1999/01/01"), as.Date("2000/01/01"),
    by = "day"
  ), size = 150))

iris[45, 2] <- as.numeric(NA)
iris[37, 3] <- as.numeric(NA)
iris[78, 4] <- as.numeric(NA)
iris[9, 5] <- as.numeric(NA)
iris[15, 6] <- as.factor(NA)

set.seed(456)

iris_split <- iris %>%
  initial_split(strata = Sepal.Length)


iris_training <- training(iris_split)
iris_testing <- testing(iris_split)

iris_rf_model <- rand_forest(
  mtry = 10,
  min_n = 10,
  trees = 500
) %>%
  set_engine("ranger") %>%
  set_mode("regression")


base_rec <- recipe(Sepal.Length ~ .,
  data = iris_training
) %>%
  step_impute_knn(Sepal.Width, Petal.Length, Petal.Width, Species, Plucked) %>%
  step_date(Plucked) %>%
  step_dummy(Species)

iris_workflow <- workflow() %>%
  add_model(iris_rf_model) %>%
  add_recipe(base_rec)

iris_rf_wkfl_fit <- iris_workflow %>%
  last_fit(iris_split)
#> x train/test split: preprocessor 1/1: Error: Assigned data `pred_vals` must be compatible wi...
#> Warning: All models failed. See the `.notes` column.
Created on 2021-06-15 by the reprex package (v2.0.0)

这是reprex，它不会出现错误：

library(tidyverse)
library(tidymodels)

iris[45, 2] <- as.numeric(NA)
iris[37 ,3] <- as.numeric(NA)
iris[78, 4] <- as.numeric(NA)
iris[9, 5] <- as.numeric(NA)

set.seed(123)

iris_split <- iris %>% 
  initial_split(strata = Sepal.Length)

iris_training <- training(iris_split)
iris_testing <- testing(iris_split)

iris_rf_model <- rand_forest(
  mtry = 5,
  min_n = 5,
  trees = 500) %>%
  set_engine("ranger") %>%
  set_mode("regression")


base_rec <- recipe(Sepal.Length ~ .,
                   data = iris_training) %>% 
  step_impute_knn(Sepal.Width, Petal.Length, Petal.Width, Species) %>%
  step_dummy(Species)

iris_workflow <- workflow() %>% 
  add_model(iris_rf_model) %>% 
  add_recipe(base_rec)

iris_rf_wkfl_fit <- iris_workflow %>%
  last_fit(split = iris_split)
Created on 2021-06-15 by the reprex package (v2.0.0)

提前致谢！M。

4

1 回答 1

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我想我找到了答案并想与您分享。关键是将日期转换为数值。然后估算很容易。这是一个reprex.

library(tidyverse)
library(tidymodels)

iris <- iris %>%
  mutate(Plucked = sample(seq(as.Date("1999/01/01"), as.Date("2000/01/01"),
    by = "day"
  ), size = 150))

iris[45, 2] <- as.numeric(NA)
iris[37, 3] <- as.numeric(NA)
iris[78, 4] <- as.numeric(NA)
iris[9, 5] <- as.numeric(NA)
iris[15, 6] <- as.factor(NA)

set.seed(456)

iris_split <- iris %>%
  initial_split(strata = Sepal.Length)


iris_training <- training(iris_split)
iris_testing <- testing(iris_split)

iris_rf_model <- rand_forest(
  mtry = 10,
  min_n = 10,
  trees = 500
) %>%
  set_engine("ranger") %>%
  set_mode("regression")


base_rec <- recipe(Sepal.Length ~ .,
  data = iris_training
) %>% 
  step_mutate_at(
    where(lubridate::is.Date),
    fn = ~ as.numeric(lubridate::ymd(.x))
  ) %>%
  step_impute_bag(c("Plucked")) %>% 
  step_impute_knn(Sepal.Width, Petal.Length, Petal.Width, Species) %>%
  step_dummy(Species)

iris_workflow <- workflow() %>%
  add_model(iris_rf_model) %>%
  add_recipe(base_rec)

iris_rf_wkfl_fit <- iris_workflow %>%
  last_fit(iris_split)
#> ! train/test split: preprocessor 1/1, model 1/1: 10 columns were requested but there were 6 ...
Created on 2021-06-29 by the reprex package (v2.0.0)

如果您想在拟合之前从数字恢复为日期，可以通过在代码中添加以下行来实现：

step_mutate_at(c("Plucked"), fn = ~ as.Date(.x, origin = "1970-01-01 UTC"))

再次感谢，M。

于 2021-06-29T10:21:10.357 回答