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我正在使用 hibernate-generic-dao 进行搜索功能。因为如果它们在列字段上具有相同的值，我只需要显示其中一条记录。但我不确定如何通过搜索/过滤功能来实现这一点。

package com.googlecode.genericdao.search;

PersonContact domain object:
...
@Column(name = "group_key", length = 20)
    public String getGroupKey() {
        return groupKey;
    }

@Formula(value = "(SELECT status from person_contact m " + 
                " WHERE m.case = case AND m.movement_id = movement_id )")    
    public String getActiveRecord() {
        return activeRecord;
    }
...

Search search = new Search();
search.addFilterNotNull("groupKey"); //groupKey is the field I want to use "group by / unqiue" with it
search.addFilterEqual("type","C");
search.addFilterCustom("{activeRecord} != 'I' ");
search.setMaxResults(limit);//for paging
search.setFirstResult(startIdx);
SearchResult<PersonContact> resultObj = PersonContactDAO.searchAndCount(search);
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1 回答 1

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您可能应该通过在该项目的存储库中打开一个问题来问这个问题：https ://github.com/vincentruan/hibernate-generic-dao

似乎该项目已被放弃，因此除非您想深入研究细节，否则您可能应该尝试摆脱它。

于 2021-06-14T13:16:13.693 回答